Since the second equation gives a value for a, we can substitute it into the other equation to find a value for B.
Let's substitute b-2 into the first equation wherever there is an a.
a - 3b = 4
(b-2) - 3b = 4
b - 2 - 3b = 4
-2 - 2b = 4
-2b = 6
b = -3
Now let's find a by substituting -3 into either of the equations to find the value of a.
a = b - 2
a = -3 - 2
a = -5
So your solution set is (-5, -3)
Answer:
64.6 km/h
Step-by-step explanation:
18:14 = 18h 14'
1h = 60'
18h = 17h + 60'
18h14' = 17h + 60' ´14' = 17h 74'
then:
17h 74'
-17h 22'
= 0h 52'
the train travelled 56km at 52 minutes
56km/52minutes
1 hour = 60 minutes
52 minutes = 52/60 = 0.86667 hours
then:
56km/52minutes = 56km/0.86667hours
= 64.615 km/hours
Add what they ate
2/3 + 1/4 =
11/12
Then subtract that from the whole pizza
12/12 - 11/12 =
1/12
1/12 of the pizza is left
Please mark as brainiest
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±
)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation:
