Answer:
8 x 10^-8 C on both the spheres.
Explanation:
Number of electrons added to A = 1 x 10^12
As the sphere A and B are identical to each other so the charge is shared equally.
Charge of one electron = 1.6 x 10^-19 C
Charge on A after wards
= number of electrons after wards x charge of one electron
qA = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C
Similarly, the charge on sphere B afterwards
= number of electrons after wards x charge of one electron
qB = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C
Answer:
2.33 nC, 4.67 nC
Explanation:
when the two spheres are connected through the wire, the total charge (Q=7.00 nC) re-distribute to the two sphere in such a way that the two spheres are at same potential:
(1)
Keeping in mind the relationship between charge, voltage and capacitance:

we can re-write (1) as
(2)
where:
Q1, Q2 are the charges on the two spheres
C1, C2 are the capacitances of the two spheres
The capacitance of a sphere is given by

where R is the radius of the sphere. Substituting this into (2), we find
(3)
we also know that sphere 2 has twice the diameter of sphere 1, so the radius of sphere 2 is twice the radius of sphere 1:

So the eq.(3) becomes

And re-arranging it we find:

And since we know that the total charge is

we find

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Answer:
0.32 s
Explanation:
Initial angular speed: 
Final angular speed: 
Angular rotation: 
The angular acceleration of the drill can be found by using the equation:

Re-arranging it, we find
, the angular acceleration:

Now we want to know the time t the drill takes to accelerate from

to

This can be found by using the equation

where
is the angular acceleration we found previously. Solving for t,
