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babunello [35]
3 years ago
6

You apply 100.0 N of force to a machine. The machine applies 20.0 N of force to the load. What is the mechanical advantage of th

e machine?
Physics
2 answers:
allsm [11]3 years ago
6 0
This machine has a mechanical advantage of 1/5, 20%, or no realistic advantage. This is because the machine transferred 80 N into external systems of the original 100 N applied.

Hope this helps!
max2010maxim [7]3 years ago
6 0

Answer:

0.20

Explanation:

The mechanical advantage of a machine is given by:

MA=\frac{F_{out}}{F_{in}}

where

Fout is the output force (the load)

Fin is the input force (the effort)

For this machine, the input force is 100.0 N, while the output force is 20.0 N, so the mechanical advantage is

MA=\frac{20.0 N}{100.0 N}=0.20

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A block with mass of 10 kg is on a frictionless surface. One hand on the left side of the block is pushing it to the right. A se
igomit [66]

Answer:

W_2=-12J

Explanation:

The work of force 2 will be given by the vectorial equation W_2=F_2.d. We know the value of F_1 and have information about its movement, which relates to the net force F=F_1+F_2.

About this movement we can obtain the acceleration using the equation v_f^2=v_i^2+2ad. Since it departs from rest we have a=\frac{v_f^2}{2d}.

And then using Newton's 2dn Law we can obtain the net force F=ma, thus we will have F_2=F-F_1=ma-F1=\frac{mv_f^2}{2d}-F_1

And we had the work done by force 2 as:

W_2=F_2.d=\frac{mv_f^2}{2}-F_1d

(The sign will be given algebraically since we take positive the direction to the right.)

With our values:

W_2=\frac{(10kg)(2m/s)^2}{2}-(8N)(4m)=-12J

<em>Another (shorter but maybe less intuitive way for someone who is learning) way of doing this would have been to say that the work done by both forces would be equal to the variation of kinetic energy:</em>

<em>W_1+W_2=K_f-K_i=K_f=\frac{mv_f^2}{2}</em>

<em>Which leads us to the previous equation straightforwardly.</em>

6 0
3 years ago
Where can I find springs that are the same size as the ones in a mechanical pencil
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Answer:

Staples, Bestbuy, Maybe Homedepot

Explanation:

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A car starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds. What is its acceleration? What is the car’s displacement? (Demons
disa [49]

The acceleration of a car that starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds is 2.6m/s².

<h3>How to calculate acceleration?</h3>

The acceleration of a moving object can be calculated using the following formula:

a = (v - u)/t

Where;

  • a = acceleration (m/s²)
  • v = final velocity (m/s)
  • u = initial velocity (m/s)
  • t = time (s)

According to this question, a car starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds.

a = (25.5 - 12.5)/5

a = 13.0/5

a = 2.6m/s²

Therefore, the acceleration of a car that starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds is 2.6m/s².

Learn more about acceleration at: brainly.com/question/12550364

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4 0
2 years ago
Between which two points of a concave mirror should an object be placed to obtain a magnificati of -3​
kobusy [5.1K]

Answer:

When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.

When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.

Explanation:

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