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3 years ago

One Solution3x + 9 + 4x + 3 =

Mathematics

1 answer:

Taya2010 [7]3 years ago

6 0

3x + 9 + 4x + 3 = 7x + 12

Add 3x + 4x =7x

Add 9 + 3 = 12

Answer: 7x + 12

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5/x+3 take away 1/x-2 equals to 1. solve two possible answers for x

satela [25.4K]

Answer:

<h3><u>Solution</u><u>:</u><u>-</u></h3>

First write the given equation

$\qquad{:}\longrightarrow$ $\sf \dfrac {5}{x+3}-\dfrac{1}{x-2}=1$

$\qquad{:}\longrightarrow$ $\sf \dfrac {5 (x-2)-1 (x+3)}{(x+3)(x-2)}=1$

$\qquad{:}\longrightarrow$ $\sf \dfrac {5x-10-x }{x^2-6x-6} =1$

use cross multiplication method

$\qquad{:}\longrightarrow$ $\sf 5x-x-10=x^2-6x-6$

$\qquad{:}\longrightarrow$ $\sf x^2-6x-6=4x-10$

$\qquad{:}\longrightarrow$ $\sf x^2-6x-4x-6+10=0$

$\qquad{:}\longrightarrow$ $\sf x^2-10x+4=0$

use quadratic formula

$\qquad{:}\longrightarrow$ $\sf x=\dfrac {-b\underline{+}\sqrt {b^2-4ac}}{2a}$

$\qquad{:}\longrightarrow$ $\sf x=\dfrac {10\underline{+}\sqrt {(-10)^2-4×1×4}}{2×1}$

$\qquad{:}\longrightarrow$ $\sf x=\dfrac {10\underline{+}\sqrt{100-16}}{2}$

$\qquad{:}\longrightarrow$ $\sf x=\dfrac {10\underline{+}\sqrt {84}}{2}$

$\qquad{:}\longrightarrow$ $\sf x=\dfrac {10+\sqrt {84}}{2}\quad or\quad x=\dfrac {10-\sqrt{84}}{2}$

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Step-by-step explanation:

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Step-by-step explanation:

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What added to what equals -9

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One Solution3x + 9 + 4x + 3 =​

One Solution3x + 9 + 4x + 3 =