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I am Lyosha [343]

3 years ago

5

Helppppppppppppppppppppppppp

1 answer:

Llana [10]3 years ago

6 0

Answer:
2log₅(x) - 2log₅(4)

Explanation:
Note the following rules before we begin:
log(a) - log(b) = log(a/b)
2log(a) = log(a²)

Now, for the given, we will work backwards as follows:
log₅(x/4)² = 2 [ log₅(x) - log₅(4)]
= 2log₅(x) - 2log₅(4)

Hope this helps :)

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A line has slope 5/6 and y-intercept-3

viva [34]

Answer:

The equation would be y = 5/6x - 3

Step-by-step explanation:

8 0

2 years ago

If f (x) = StartRoot x EndRoot + 12 and g (x) = 2 StartRoot x EndRoot, what is the value of (f – g)(144)

Luda [366]

The value of (f-g)(144) is 0

Step-by-step explanation:

We are given:

$f(x)=\sqrt{x}+12\,\,and\,\,\\ g(x)=2\sqrt{x}$

We need to find value of (f-g)(144)

We will put x=144 for both f(x) and g(x)

$(f-g)(144)=f(144)-g(144)\\=\sqrt{144}+12-(2\sqrt{12})\\=12+12-(2(12)\\=24-24\\=0$

So, the value of (f-g)(144) is 0

Keywords: Composite Functions

Learn more about Composite Functions at:

#learnwithBrainly

4 0

3 years ago

Read 2 more answers

I need y’all please help me 5

MArishka [77]

Answer:

no she couldnt have because 10 the fee and 2 the charge added up equals 12. 12 times 3 is 36, and she paid less than 36 dollars

Step-by-step explanation:

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3 years ago

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Find m angle C<br> 62 degrees<br> 70 degrees

wlad13 [49]

Answer:

48°

Step-by-step explanation:

..,.............,...........

CDB = ABD( given)

CBD= ADB( given)

Now,

CBD+CDB+C = 180°

70°+62°+ C = 180°

C= 180°-132°

C= 48°

7 0

2 years ago

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The height of a trapezoid is 8 in. And its area is 96 in2. One base of the trapezoid is 6 inches longer than the other base. Wha

Vsevolod [243]

Answer:

The lengths of the bases are 9 inches and 15 inches.

Step-by-step explanation:

The area of trapezoid is

$=\frac12(\textrm{ sum of parallel sides})\times height$

Given that the height of a trapezoid is 8 in. and its area is 96 in².

Assume the bases of the trapezoid be b₁ and b₂.

Since one base of the trapezoid 6 in. longer than the other.

Let, b₁=b₂+6

The area of the trapezoid is

$=\frac 12 (b_1+b_2)\times8$ in²

$=\frac12 (b_2+6+b_2)\times 8$ in²

$=\frac12(2b_2+6)\times8$ in²

According to the problem,

$\frac12(2b_2+6)\times8 =96$

$\Rightarrow 2b_2+6=\frac{96\times 2}{8}$ [ Multiplying $\frac28$ ]

$\Rightarrow 2b_2+6=24$

$\Rightarrow 2b_2=24-6$

$\Rightarrow 2b_2=18$

$\Rightarrow b_2=\frac{18}{2}$

$\Rightarrow b_2=9$

Then, $b_1=b_2+6$

=9+6

=15 in

The lengths of the bases are 9 inches and 15 inches.

5 0

3 years ago