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3 years ago

Solve the inequality y−5(y+1)≥2y−5 and write the solution in interval notation.

Mathematics

1 answer:

morpeh [17]3 years ago

5 0

Answer:

0≥6y

Step-by-step explanation:

y-5(y+1)≥2y-5

y-5y-5≥2y-5

-4y≥2y

0≥6y

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Find the solution for the equation y=4x-3

weqwewe [10]

Answer:

(-4,-19)

Step-by-step explanation:

Substitute the points into the equation and see if it is true

y = 4x-3

-3 = 4(4) -3

-3 = 16-3

-3 = 13 false

-19 = 4(-4) -3

-19 = -16-3

-19 -19 true

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3 years ago

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The domain for f(x) and g(x) is the set of all real numbers.

Tom [10]

Answer:

Option B

Step-by-step explanation:

=> $f(x) = 3x+5$

=> $g(x) = x^2$

Subtracting both

=> $(f-g)(x) = 3x+5-x^2$

Assembling

=> $(f-g)(x) = -x^2+3x+5$

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3 years ago

Figure B is a scaled copy of Figure A.

zimovet [89]

Answer:

Step-by-step explanation:

We are told that figure B is a scaled copy of B, which means figure A was enlarged by a certain scale factor to get a similar figure as A, now referred to as figure B.

The scale factor = ratio of any two corresponding sides of both similar figures.

Thus,

Scale factor of the similar figures given = 40/10 = 4.

This means that, figure A was scaled up by 4 times its original size to get figure B. Each side of figure B is 4 × the corresponding side in figure A.

Scale factor = 4

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3 years ago

Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and the e

Komok [63]

Answer:

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

Step-by-step explanation:

Independent events:

If two events, A and B, are independent, then:

$P(A \cap B) = P(A)*P(B)$

Conditional probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: At least one tag is lost

Event B: Exactly one tag is lost.

Each tag has a 40% = 0.4 probability of being lost.

Probability of at least one tag is lost:

Either no tags are lost, or at least one is. The sum of the probabilities of these events is 1. Then

$p + P(A) = 1$

p is the probability none are lost. Each one has a 60% = 0.6 probability of not being lost, and they are independent. So

p = 0.6*0.6 = 0.36

Then

$P(A) = 1 - p = 1 - 0.36 = 0.64$

Intersection:

The intersection between at least one lost(A) and exactly one lost(B) is exactly one lost.

Then

Probability at least one lost:

First lost(0.4 probability) and second not lost(0.6 probability)

First not lost(0.6 probability) and second lost(0.4 probability)

$P(A \cap B) = 0.4*0.6 + 0.6*0.4 = 0.48$

Find the probability that exactly one tag is lost, given that at least one tag is lost (write it up to second decimal place).

$P(B|A) = \frac{0.48}{0.64} = 0.75$

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

8 0

3 years ago

A firefighter uses equipment that weighs 60 pounds. The firefighter weighs x pounds. Which equation can be used to find t, the t

Ivanshal [37]

Since the total weight would be equal to the weight of the firefighter added to the weight of the equipment, the total weight would be x+60. So the answer is B. t=x+60

Hope this helps

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3 years ago

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