Can the domain or the range repeat in a function, which one?

1 answer:

8 0

We can have values repeat in the range of a function, but not in the domain. A function always has exactly one value in the range associated with a given value in the domain, but it can have multiple values in the domain associated with the same value in the range.

For example, in the equation y = x², we could say that y is a function of x (every y value except 0 has exactly 2 x values associated with it), but the equation y² = x would not describe y as a function of x (every x value except 0 would now have exactly 2 y values associated).

You might be interested in

What would be equivalent to 32 ⋅ 35?

OLga [1]

There Are Many Things That Would Be Equivalent!
What They Are Looking For Is Probably:
(30 * 5) + (5 * 2) + (30 * 30) + (30 * 2)

8 0

3 years ago

(PLEASE ANSWER ASAP!)

shtirl [24]

Mode: 43 & 81 ( They both appeared the most amount of times)
Range: 41 (Subtract the largest number with the smallest number)
Mean: 58
Min: 40 (Q1)
Max: 81 (Q3)
Med: 54 (Q2)

Hope this helps!!!

5 0

3 years ago

What is 6 divided by 25.2

mr_godi [17]

6/25.2
Multiply both sides by 5 so 25.2 is a whole number:
30/126
and then simplify by dividing by 6:
5/21 which is equal to 0.2381.

Hope this helps :)

6 0

3 years ago

A cold tablet contains the following amounts of active ingredients: acetaminophen 325 mg, chlorpheniramine maleate 2 mg, and dex

kakasveta [241]

Answer:

The number of tablets that can be prepared is 3076.

Step-by-step explanation:

The total amount of active ingredients in the tablet is the sum of the amounts provided in the formula:

$325 mg + 2mg+15 mg=342 mg$

The percentages of each component in the formula are:

Acetaminophen: $\frac{325mg*100}{342mg}=95.03$ %

Chlorpheniramine maleate: $\frac{2mg*100}{342mg} =0.58$ %

Dextromethorphan hydrobromide: $\frac{15mg*100}{342mg}=4.39$ %

If 1 Kg= $10^{6}$ mg of acetaminophen is used, the needed amount of chlorpheniramine maleate would be:

$\frac{10^{6} mg *0.58}{95.03}=6153.85 mg$

Since there are 125 g = 125000 mg of chlorpheniramine maleate, there is enough of these ingredient to run the available acetaminophen out. Thus, the total amount of active ingredients that can be prepared with 1 kg of acetaminophen is:

$\frac{10^{6}mg*100}{95.03}=1052307.7mg$