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konstantin123 [22]
4 years ago
8

Which expressions are equivalent to 3x+ 3(x + y)?

Mathematics
1 answer:
Lunna [17]4 years ago
4 0

Answer:

6 x + 3 y = 3x+ 3(x + y)  or 3 (2 x + y)

Step-by-step explanation:

all exxpressions are equivalent

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Work out the percentage change to 2 decimal places when a price of £12 is increased to £15.99
gulaghasi [49]
Hence, the percentage increment is 33.25%
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3 years ago
Sub to astronaut gaming i have 27 subs if you need help finding i will help
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i will join

Step-by-step explanation:

8 0
3 years ago
What is the 17th term in the arithmetic sequence in which a6 is 101 and a9 is 83
monitta

Answer:

The 17th term in arithmetic sequence is 68

Step-by-step explanation:

The general formula of arithmetic sequence is:

aₙ = a₁ + (n – 1)d.

We are given a₆ = 101 and a₉ = 83 and we need to find a₁₇

To find the term a₁₇ we should know a₁ and d. So we would find both

a₆ = a₁ +(6-1)d

101 = a₁ +(5)d

101 = a₁ +5d     eq(1)

and

a₉ = a₁ +(9-1)d    

83 = a₁ + 8d       eq(2)

Subtracting eq(2) from eq(1)

101 = a₁ +5d

83 = a₁ + 8d

-       -     -

__________

18 = -3d

=> d = 18/-3

=> d = -6

Putting value of d in eq(1)

101 = a₁ + 5d

101 = a₁ + 5(-3)

101 = a₁ -15

=> a₁ = 101+15

=> a₁ = 116

Now finding a₁₇:

aₙ = a₁ + (n – 1)d.

a₁₇ = 116 +(17-1)(-3)

a₁₇ = 116+(16)(-3)

a₁₇ = 116 - 48

a₁₇ = 68

So, the 17th term in arithmetic sequence is 68

3 0
3 years ago
Find how many kilometers they traveled by
Murrr4er [49]

Answer:

Step-by-step explanation:

Biking is x and bussing is y. We know that the total distance is 325. Thus, the first equation in this system is

x + y = 325 (which says that the km traveled by bike plus the km traveled by bus totaled 325 km).

We also know that the pair biked 75 km more than they rode, giving us the second equation in our system:

x = y + 75. Now we use simple substitution and plug y + 75 in for x in the first equation:

(y + 75) + y = 325 and

2y + 75 = 325 and

2y = 250 so

y = 125 km. They rode the bus for 125 km and biked for 325 - 125 which is 200. And the difference is 75 km, as it should be!

7 0
3 years ago
Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t
Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

(AO)^2=(AD)^2-(DO)^2

x^{2}=5^2-3^2

x^{2}=25-9

x^{2}=16

Upon taking square root of both sides of our equation we will get,

x=\sqrt{16}

x=\pm 4

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

(OC)^2=(DC)^2-(DO)^2

Upon substituting our given values we will get,

y^2=10^2-3^2

y^2=100-9

y^2=91

Upon taking square root of both sides of our equation we will get,

y=\sqrt{91}

y\pm 9.539392

y\pm\approx 9.54

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

\text{The length of the longer diagonal}=x+y

\text{The length of the longer diagonal}=4+9.54

\text{The length of the longer diagonal}=13.54

Therefore, the length of longer diagonal is approximately 13.54 inches.

3 0
3 years ago
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