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notsponge [240]
3 years ago
9

What is the value of this expression? 4/15+3/5−2/3 Enter your answer in the box as a fraction in simplest form.

Mathematics
2 answers:
forsale [732]3 years ago
7 0

Answer:

\frac{4}{15}  +  \frac{3}{5}  -  \frac{2}{3}

\frac{4 \times 1}{15 \times 1}  +  \frac{3 \times 3}{5 \times 3}  -  \frac{2 \times 5}{3 \times 5}

\frac{4}{15}  +  \frac{9}{15}  -  \frac{10}{15}

\frac{4 + 9 - 10}{15}

\frac{13 - 10}{15}

\frac{3}{15}

\frac{1}{5}

hope it helps you :)

have a great day

allochka39001 [22]3 years ago
5 0

Answer:

1/5

Step-by-step explanation:

pls mark brainliest

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A function f(x)=3x+12.
seraphim [82]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822258

_______________


•  Function:   f(x) = 3x + 12.


A.  Finding the inverse of f.

The composition of f with its inverse results in the identity function:

(f o g)(x) = x

f[ g(x) ] = x

3 · g(x) + 12 = x

3 · g(x) = x – 12

              x – 12
g(x)  =  ⸺⸺
                 3

               x 
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               3

________


B.  Verifying that the composition of f and g gives us the identity function:

•  \mathsf{(f\circ g)(x)}

\mathsf{=f\big[g(x)\big]}\\\\\\ \mathsf{=3\cdot \left(\dfrac{x}{3}-4\right)+12}\\\\\\&#10;\mathsf{=\diagup\hspace{-7}3\cdot \dfrac{x}{\diagup\hspace{-7}3}-3\cdot 4+12}\\\\\\&#10;\mathsf{=x-12+12}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}


and also

•  \mathsf{(g\circ f)(x)}

\mathsf{=g\big[f(x)\big]}\\\\\\ \mathsf{=\dfrac{f(x)}{3}-4}\\\\\\ \mathsf{=\dfrac{3x+12}{3}-4}\\\\\\&#10;\mathsf{=\dfrac{\diagup\hspace{-7}3\cdot (x+4)}{\diagup\hspace{-7}3}-4}\\\\\\&#10;\mathsf{=x+4-4}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}

________


C.  Since f and g are inverse, then

f(g(– 2))

= (f o g)(– 2)

= – 2          <span>✔
</span>

•  Call h the compositon of f and g. So,

h(x) = (f o g)(x)

h(x) = x


As you can see above, there is no restriction for h. Therefore, the domain of h is R (all real numbers).


I hope this helps. =)

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