Answer:
Step-by-step explanation:
Integrating each term with respect to x, we get:
x^3 x^2
f(x) = 9--------- + 4------- - 4x + C
3 2
We are told that if x = 0, f(x) = -7, and so C must equal - 7.
The solution is
x^3 x^2
f(x) = 9--------- + 4------- - 4x - 7, or f(x) = 3x^3 + 2x^2 - 4x - 7
3 2
Answer:
the line crosses the parabola at (-2,4) and (3,9)
Step-by-step explanation:
y=x^2
y=x+6
set them equal to each other
x^2=x+6, now set it equal to zero
x^2-x-6=0, now find the root
(x+2)(x-3)=0, the x=-2, and x=3; now substitute into any of the equation to find the points where graphs intercept
at x= -2, y=(-2)^2=4, so one point is (-2,4)
at x=3, y=(3)^2=9, so other point is (3,9)
the line crosses the parabola at (-2,4) and (3,9)
Slope-intercept:
y=mx+b
5x-y=9
5x=y+9
y+9=5x
y=5x-9
Slope-int: y=5x-9