Y = 3x - 4.....the slope here is 3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, u flip the slope and change the sign. So we will need a slope of -1/3...see how I flipped the slope of 3/1 and made it 1/3...and then changed the sign, making it -1/3.
y = mx + b
slope(m) = -1/3
(2,1)...x = 2 and y = 1
now we sub and find b, the y int
1 = -1/3(2) + b
1 = -2/3 + b
1 + 2/3 = b
3/3 + 2/3 = b
5/3 = b
so ur perpendicular equation is : y = -1/3x + 5/3
Answer:
H
Step-by-step explanation:
it doesn't accurately reflect a representation because you still don't know exactly how much the birds and snakes are. you know what they are together but not apart and that's not acceptable
Step-by-step explanation:
I can't see good the picture
They are the same measurements, because:
from 10x + 5, first do vertical angle.
then, alternate interior angle,
then vertical angle again,
and another alternate interior angle.
For each vertical and alternate interior angles, the measurements stay the same.
Set them equal to each other, isolate and solve for x.
10x + 5 = 11x - 1
First, isolate the x. Subtract 10x from both sides, and add 1 to both sides
10x (-10x) + 5 (+1) = 11x (-10x) -1 (+1)
Simplify
5 + 1 = 11x - 10x
6 = x
x = 6
6 is your answer for x.
hope this helps
Answer:
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Step-by-step explanation:
Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.
Let five years ago be group I X and as of now be group II Y
(Two tailed test at 5% level of significance)
Group I Group II combined p
n 270 300 570
favor 120 140 260
p 0.4444 0.4667 0.4561
Std error for differene = 
p difference = -0.0223
Z statistic = p diff/std error = -1.066
p value =0.2864
Since p value >0.05, we accept null hypothesis.
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
