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Firlakuza [10]
3 years ago
7

(3x-70) (3y+40) 120 x

Mathematics
1 answer:
Andru [333]3 years ago
8 0
(3y+40)+(3x-70)=180

3y+3x-30=180
3y+3x=210
3(y+x)=210
y+x=70
x=70-y

meanwhile 180-120=x therefore x=60
therefore
60=70-y y=10
so x=60 y=10
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Luden [163]

Answer:

B and C work. A and D do not.

Step-by-step explanation:

This is one of those questions that you have to go through each answer to see what the results are. You don't have to go far to eliminate A and D so let's do that first.

A]

5n + 6

Let n = 1

5(1) + 6

5 + 6= 11

However there is trouble beginning with n = 2

5*2 + 6

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16     All you need is one wrong answer and the choice is toast. So A won't work.

================

Try D

6(n - 1)+ 5

n=0

6*(-1) + 5

-6 + 5

- 1

And D has been eliminated with just 1 attempt. n= 2 or n = 1 would be even worse.  D is not one of the answers.

=============

B

Let n = 1

6(1) + 5

6 + 5

11 The first term works.

n = 2

6*(2) + 5

12 + 5

17 and n = 2 works as well. Just in case it is hard to believe, let's try n = 3 because so far, everything is fine.

n = 3

6*(3) + 5

18 + 5

23 And this also works. I'll let you deal with n = 4

========

C

n = 0

6(0 + 1) + 5

6*1 + 5

6 + 5

11

n = 1

6(1 + 1) + 5

6*2 + 5

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17 which works.

So C is an answer.

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3 years ago
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ZanzabumX [31]
Ok lets go ahead and see if the following answers can help:
<span>A) if p = 0.2 then C(p) = 157.52
B) if p = 0.95 then C(p) = 753.86
C) smallest p value that gives C(p) > or = 0. This is p = 0
D) largest INTEGER value for C(p) to exist or be >=0. This is p = 99. p = 100 gives 786000/0; does not exist. p > 101 starts giving negative numbers.
</span>I hope this has been of help
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4 0
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Step-by-step explanation:

Because 52 ÷78 =66.6

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