Question

Determine which consecutive integers the real zeros of f(x) = x^3 - 2 are located

Answer 1

Answer:

The real zero is between 1 and 2.

Step-by-step explanation:

The given function is:

$f(x)=x^3-2$

To find the zeros of this function, we set f(x)=0.

$\implies x^3-2=0$

Add 2 to both sides to obtain:

$\implies x^3=2$

Take the cube root of both sides

$\implies x=\sqrt[3]{2}$

$\implies x=1.26$

Therefore the real zero is between 1 and 2.