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S_A_V [24]
4 years ago
15

Need help with math question

Mathematics
2 answers:
jek_recluse [69]4 years ago
8 0

Answer:

(-7,4)

Step-by-step explanation:

mote1985 [20]4 years ago
4 0

Answer:

(-7,4)

Step-by-step explanation:

goal: (y-k)^2=4p(x-h)

y^2-8y=4x+12    Rearranged and added 4x and 12 on both sides

y^2-8y+(-8/2)^2=4x+12+(-8/2)^2 complete square time (add same thing on both sides)

y^2-8y+(-4)^2=4x+12+(-4)^2 (simplify inside the squares)

(y-4)^2=4x+12+16  (now write the left hand side as a square)

(y-4)^2=4x+28

(y-4)^2=4(x+7)    factored...

vertex is (-7,4)

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3 years ago
Solve the right triangle. a = 2.2 m, B = 37.7°, C = 90° 4) A) A = 52.3°, b = 0.6 m, c = 2.3 m B) A = 52.3°, b = 1.7 m, c = 2.8 m
DENIUS [597]

Answer:

B) A = 52.3°, b = 1.7 m, c = 2.8 m

Step-by-step explanation:

We know that it is a right angle triangle because C = 90°

because of that we can do 180 - 90 + 37.7

which is a=52.3

Because it is a right angle triangle, we can use sin, cos,tan

I will use sin to find the side of c

2.2 is a

sin 52.3 = 2.2/x

x= 2.2/ sin 52.3

x=2.78

You could do cos or tan but the pythagorean theorem for me is much faster

so it looks like this, a^2+b^2 =c^2

in this case we have both a and c we want b

so we rearrange

c^2-a^2=b^2

2.78^2-2.2^2= b^2

\sqrt{2.89}=b

1.7=b

therefore it would be this option B) A = 52.3°, b = 1.7 m, c = 2.8 m

6 0
3 years ago
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