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3 years ago

Please figure out ASAP

Mathematics

1 answer:

VikaD [51]3 years ago

5 0

Answer:

I believe that the answer is C because it seems to be the only reasonable answer , but i may be wrong , if i am correct please mark the brainliest

Step-by-step explanation

Answer:

x=12

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Help please I’ll give brainleiest :)

Paladinen [302]

Answer:

1 hour would be 10 $ each

Step-by-step explanation:

1)$10

2)$50

3)$80

I hope this helps

4 0

3 years ago

What is the answer to (8x-44)

kodGreya [7K]

Are you solving for x or what

3 0

3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

8 0

3 years ago

If you can help 1-12 that’s great if not just help with what you can thanks

bearhunter [10]

(1. -2) (2. 0) (3. 6) (4. 3)

5 0

3 years ago

What is the runner’s average rate of change between the hours: 0.5 and 2? mph 1.5 and 2.5? mph Average Rate of Change

lana [24]

Answer:

0.5 and 2?

mph

1.5 and 2.5?

mph

Base on these results, the runner ran at a rate between 0.5 and 2 hours than between 1.5 and 2.5 hours.

slower

Step-by-step explanation:

4 0

3 years ago

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