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solniwko [45]
3 years ago
5

PLEASE HELP!! THX

Mathematics
1 answer:
solong [7]3 years ago
5 0
Hello,
The translation t is (x,y)->(x-2,y+3)
So its inverse t^(-1)=-t is (x,y)->(x+2,y-3)

B=-t(B')=(4+2,-8-3)=(6,-11)

You might be interested in
What is -3 (x+2) = 16 -x
arsen [322]

Answer:

x = -11

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Distributive Property

<u>Algebra I</u>

Equality Properties

  1. Multiplication Property of Equality
  2. Division Property of Equality
  3. Addition Property of Equality
  4. Subtraction Property of Equality

Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

-3(x + 2) = 16 - x

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Distributive Property] Distribute -3:                                                                -3x - 6 = 16 - x
  2. [Addition Property of Equality] Add <em>x</em> on both sides:                                     -2x - 6 = 16
  3. [Addition Property of Equality] Add 6 on both sides:                                    -2x = 22
  4. [Division Property of Equality] Divide -2 on both sides:                                x = -11
5 0
2 years ago
Owen bought 9 chicken wings for $15.30. What was the cost of the wings, in dollars per wing?
kykrilka [37]

Answer:

1.70

Step-by-step explanation:

15.30 ÷ 9 = 1.70

1.70 dollars per chicken wing

I hope this helps

7 0
3 years ago
The median of a continuous random variable having distribution function F is that value m such that F(m) = 1/2 . That is, a rand
neonofarm [45]

Answer:

Step-by-step explanation:

To find median and mode for

a) In a uniform distribution median would be

(a+b)/2 and mode = any value

b) X is N

we know that in a normal bell shaped curve, mean = median = mode

Hence mode = median = \mu

c) Exponential with parameter lambda

Median = \frac{ln2}{\lambda }

Mode =0

7 0
3 years ago
One zero of the polynomial function f(x) = x3 + x2 + 20x is x = 0. What are the zeros of the polynomial function?
daser333 [38]

Answer:

The correct option is C

Step-by-step explanation:

if f(x)= x3 + x2 - 20x

Replace f(x) by y

y = x3 + x2 - 20x

0 =x3 + x2 - 20x

x3 + x2 - 20x = 0

Take out x as a common:

x(x2+x-20)=0

Find factors of x2+x+20.

x(x^2+4x-5x-20) = 0

x{x(x+4)-5(x+4)}=0

x(x+4)(x-5)=0

Set x= 0

x=0 , x+4=0 , x-5 =0

x=0, x=0-4 , x=0+5

x=0, x= -4, x=5

x=(0,5,-4)

The correct option is C....

6 0
3 years ago
Read 2 more answers
PLEASE HELP IM GIVING 5 STAR RATINGS
erica [24]

Answer:

a. 5 + 2m

b. 5m

c. 40m + 35

Step-by-step explanation:

5 0
3 years ago
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