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Over [174]
3 years ago
12

URGENT! Please answer

Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0
Just solve for each side
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I need help with this question
lina2011 [118]
Ratio: 3/4 : 1/2

We can also write this as:

3/4 / 1/2

Flip the 2nd fraction and multiply:

3/4 * 2/1

Multiply the numerators and denominators together:

6/4

Simplify:

3/2
8 0
3 years ago
Read 2 more answers
You have a part time job. You work for 3 hours on Friday and 6 hours on Saturday. You also receive an allowance of $20 per week.
Svetradugi [14.3K]
$92 - $20 = $72, because we shouldn't take allowance into account
3 + 6 = 9, because that is the total number of hours this person works per week
We should just do this:
72 / 9 = 8
This means that this person earns $8 per hour at his part time job. 
8 0
2 years ago
Explore rectangular and triangular prisms and their two-
suter [353]

Answer:24

Step-by-step explanation:

4 0
2 years ago
How do you do this??
ruslelena [56]

Answer:

bxc+ax32=0

Step-by-step explanation:

7 0
2 years ago
A telemarketer is successful at getting people to donate money for her organization in 55% of all calls she makes. She must get
Tems11 [23]
An interesting twist to a binomial distribution problem.

Given:
p=55%=0.55 for probability of success in solicitation
x=4=number of successful solicitations
n=number of calls to be made
P(x,n,p)>=89.9%=0.899  (from context, it is >= and not =, which is almost impossible)

From context of question, all calls are assumed independent, with constant probability of success, so binomial distribution is applicable.

The number of successes, x, is then given by
P(x)=C(n,x)p^x(1-p)^{n-x}where
p=probability of success
n=number of trials
x=number of successesC(n,x)=\frac{n!}{x!(n-x)!}

Here we need n such that
P(x,n,p)>=0.899
given
x>=4, p=0.55, which means we need to find

Method 1: if a cumulative binomial distribution table is available, we can look up n=9,10,11 and find
P(x>=4,9,0.55)=0.834
P(x>=4,10,0.55)=0.898
P(x>=4,11,0.55)=0.939
So she must make (at least) 11 calls to make sure the probability of meeting her quota is 89.9% or more.

Method 2: using technology.
Similar to method 1, we can look up the probabilities directly, for n=9,10,11
P(x>=4,9,0.55)=0.834178
P(x>=4,10,0.55)=0.8980051
P(x>=4,11,0.55)=0.9390368

Method 3: using simple calculator
Here we need to calculate the probabilities for each value of n=10,11 and sum the probabilities of FAILURE S=P(0,n,0.55)+P(1,n,0.55)+P(2,n,0.55)+P(3,n,0.55)
so that the probability of success is 1-S.
For n=10,
P(0,10,0.55)=0.000341
P(1,10,0.55)=0.004162
P(2,10,0.55)=0.022890
P(3,10,0.55)=0.074603
So that
S=0.000341+0.004162+0.022890+0.074603
=0.101995
and Probability of getting 4 successes (or more) 
=1-S
=0.898005, missing target by 0.1%

So she will have to make 11 phone calls, bring up the probability to 93.9%.  The work is similar to that of n=10.
8 0
3 years ago
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