Answer:
not statistically significant at ∝ = 0.05
Step-by-step explanation:
Sample size( n ) = 61
Average for student leader graduates to finish degree ( x') = 4.97 years
std = 1.23
Average for student body = 4.56 years
<u>Determine if the difference between the student leaders and the entire student population is statistically significant at alpha</u>
H0( null hypothesis ) : u = 4.56
Ha : u ≠ 4.56
using test statistic
test statistic ; t = ( x' - u ) / std√ n
= ( 4.97 - 4.56 ) / 1.23 √ 61
= 2.60
let ∝ = 0.05 , critical value = -2.60 + 2.60
Hence we wont fail to accept H0
This shows that the difference between the student leaders and the entire student population is not statistically significant at ∝ = 0.05
Given:
An equation in a coincidental system of two linear equations:
2x + 3y = -27
The other equation is
_y = _x - 102
Rearrange the second equation to be identical to the first
_y - _x = -102
Determine the factor, -102/-27 = 3.78
for x, 2 * 3.78 = 7.56
for y, 3 * 3.78 = 11.33
The second equation, 11.33y - 7.56x = -102
Answer:
We know that angle 2 is 63. We also know that 2 and 3 are vertical pairs.
Therefor, they are congruent with one another.
Angle 3 is 63.
(5)2 which is 5 times 2. The answer is 10.
