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Lady bird [3.3K]
3 years ago
10

3. A researcher randomly selects a sample of 61 former student leaders from a list of graduates of UNCG who had participated in

leadership positions while a student. She discovered that it has taken an average of 4.97 years for these student leader graduates to finish their degrees, with a standard deviation of 1.23. The average for the entire student body is 4.56 years. Is the difference between student leaders and the entire student population statistically significant at the alpha
Mathematics
1 answer:
Sophie [7]3 years ago
3 0

Answer:

not statistically significant at ∝ = 0.05

Step-by-step explanation:

Sample size( n )  = 61

Average for student leader graduates to finish degree ( x') = 4.97 years

std = 1.23

Average for student body = 4.56 years

<u>Determine if the difference between the student leaders and the entire student population is statistically significant at alpha</u>

H0( null hypothesis ) : u = 4.56

Ha : u ≠ 4.56

using test statistic

test statistic ; t = ( x' - u ) / std√ n

                        = ( 4.97 - 4.56 ) / 1.23 √ 61

                        = 2.60

let ∝ = 0.05 , critical value = -2.60 + 2.60

Hence we wont fail to accept  H0

This shows that the difference between the student leaders and the entire student population is not statistically significant at ∝ = 0.05

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In 5 minutes a conveyor belt moves 300 pounds of receyclable aluminum from the delievery truck a smaller belt moves the same qua
ladessa [460]

Answer:

It will take 3.214 minutes.

Step-by-step explanation:

<em>It is given that, the conveyor belt transports 300 cans in 5 mins and the smaller belt transports 300 cans in 9 minutes.</em>

Thus , the speed of conveyor belt is,

= \frac{300}{5} = 60 cans per minute

and of smaller belt is,

=  \frac{300}{9} = \frac{100}{3} cans per minute

Thus, when both are used together,

<em>conveyor belt will transport (60)(t) cans and smaller belt will transport ( \frac{100}{3})(t) cans per minute.</em>

Thus the equation becomes,

300 = (60)(t) + (\frac{100}{3})(t) = (\frac{280}{3})(t)

t = \frac{(300)(3)}{280} = \frac{45}{14} = 3.214 minutes

3 0
3 years ago
Work out 3/4 + 4/7 what is the answer to this question
worty [1.4K]

Answer:

1 and 9/28

Step-by-step explanation:

you need to put everything over the same denominator

21/28+16/28=37/28

this can be written as  1 9/28

7 0
3 years ago
What’s the answer for y= (x-2)^2 +2 {x&lt;4.5}
stealth61 [152]

Answer:

x<4.5

Step-by-step explanation:

y =(x-2)^2 +2 {x<4.5}

add the power and then divide by 2 you get 4.5

8 0
3 years ago
Is the formula for percentages compound interest is P=I/N???
vampirchik [111]

Answer an essay on nothing

Step-by-step explanation:

In philosophy there is a lot of emphasis on what exists. We call this ontology, which means, the study of being. What is less often examined is what does not exist.

It is understandable that we focus on what exists, as its effects are perhaps more visible. However, gaps or non-existence can also quite clearly have an impact on us in a number of ways. After all, death, often dreaded and feared, is merely the lack of existence in this world (unless you believe in ghosts). We are affected also by living people who are not there, objects that are not in our lives, and knowledge we never grasp.

Upon further contemplation, this seems quite odd and raises many questions. How can things that do not exist have such bearing upon our lives? Does nothing have a type of existence all of its own? And how do we start our inquiry into things we can’t interact with directly because they’re not there? When one opens a box, and exclaims “There is nothing inside it!”, is that different from a real emptiness or nothingness? Why is nothingness such a hard concept for philosophy to conceptualize?

Let us delve into our proposed box, and think inside it a little. When someone opens an empty box, they do not literally find it devoid of any sort of being at all, since there is still air, light, and possibly dust present. So the box is not truly empty. Rather, the word ‘empty’ here is used in conjunction with a prior assumption. Boxes were meant to hold things, not to just exist on their own. Inside they might have a present; an old family relic; a pizza; or maybe even another box. Since boxes have this purpose of containing things ascribed to them, there is always an expectation there will be something in a box. Therefore, this situation of nothingness arises from our expectations, or from our being accustomed. The same is true of statements such as “There is no one on this chair.” But if someone said, “There is no one on this blender”, they might get some odd looks. This is because a chair is understood as something that holds people, whereas a blender most likely not.

The same effect of expectation and corresponding absence arises with death. We do not often mourn people we only might have met; but we do mourn those we have known. This pain stems from expecting a presence and having none. Even people who have not experienced the presence of someone themselves can still feel their absence due to an expectation being confounded. Children who lose one or both of their parents early in life often feel that lack of being through the influence of the culturally usual idea of a family. Just as we have cultural notions about the box or chair, there is a standard idea of a nuclear family, containing two parents, and an absence can be noted even by those who have never known their parents.

This first type of nothingness I call ‘perceptive nothingness’. This nothingness is a negation of expectation: expecting something and being denied that expectation by reality. It is constructed by the individual human mind, frequently through comparison with a socially constructed concept.

Pure nothingness, on the other hand, does not contain anything at all: no air, no light, no dust. We cannot experience it with our senses, but we can conceive it with the mind. Possibly, this sort of absolute nothing might have existed before our universe sprang into being. Or can something not arise from nothing? In which case, pure nothing can never have existed.

If we can for a moment talk in terms of a place devoid of all being, this would contain nothing in its pure form. But that raises the question, Can a space contain nothing; or, if there is space, is that not a form of existence in itself?

This question brings to mind what’s so baffling about nothing: it cannot exist. If nothing existed, it would be something. So nothing, by definition, is not able to ‘be’.

Is absolute nothing possible, then? Perhaps not. Perhaps for example we need something to define nothing; and if there is something, then there is not absolutely nothing. What’s more, if there were truly nothing, it would be impossible to define it. The world would not be conscious of this nothingness. Only because there is a world filled with Being can we imagine a dull and empty one. Nothingness arises from Somethingness, then: without being to compare it to, nothingness has no existence. Once again, pure nothingness has shown itself to be negation.

4 0
2 years ago
The joint probability density function of X and Y is given by fX,Y (x, y) = ( 6 7 x 2 + xy 2 if 0 &lt; x &lt; 1, 0 &lt; y &lt; 2
fredd [130]

I'm going to assume the joint density function is

f_{X,Y}(x,y)=\begin{cases}\frac67(x^2+\frac{xy}2\right)&\text{for }0

a. In order for f_{X,Y} to be a proper probability density function, the integral over its support must be 1.

\displaystyle\int_0^2\int_0^1\frac67\left(x^2+\frac{xy}2\right)\,\mathrm dx\,\mathrm dy=\frac67\int_0^2\left(\frac13+\frac y4\right)\,\mathrm dy=1



b. You get the marginal density f_X by integrating the joint density over all possible values of Y:

f_X(x)=\displaystyle\int_0^2f_{X,Y}(x,y)\,\mathrm dy=\boxed{\begin{cases}\frac67(2x^2+x)&\text{for }0

c. We have

P(X>Y)=\displaystyle\int_0^1\int_0^xf_{X,Y}(x,y)\,\mathrm dy\,\mathrm dx=\int_0^1\frac{15}{14}x^3\,\mathrm dx=\boxed{\frac{15}{56}}

d. We have

\displaystyle P\left(X

and by definition of conditional probability,

P\left(Y>\dfrac12\mid X\frac12\text{ and }X

\displaystyle=\dfrac{28}5\int_{1/2}^2\int_0^{1/2}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy=\boxed{\frac{69}{80}}

e. We can find the expectation of X using the marginal distribution found earlier.

E[X]=\displaystyle\int_0^1xf_X(x)\,\mathrm dx=\frac67\int_0^1(2x^2+x)\,\mathrm dx=\boxed{\frac57}

f. This part is cut off, but if you're supposed to find the expectation of Y, there are several ways to do so.

  • Compute the marginal density of Y, then directly compute the expected value.

f_Y(y)=\displaystyle\int_0^1f_{X,Y}(x,y)\,\mathrm dx=\begin{cases}\frac1{14}(4+3y)&\text{for }0

\implies E[Y]=\displaystyle\int_0^2yf_Y(y)\,\mathrm dy=\frac87

  • Compute the conditional density of Y given X=x, then use the law of total expectation.

f_{Y\mid X}(y\mid x)=\dfrac{f_{X,Y}(x,y)}{f_X(x)}=\begin{cases}\frac{2x+y}{4x+2}&\text{for }0

The law of total expectation says

E[Y]=E[E[Y\mid X]]

We have

E[Y\mid X=x]=\displaystyle\int_0^2yf_{Y\mid X}(y\mid x)\,\mathrm dy=\frac{6x+4}{6x+3}=1+\frac1{6x+3}

\implies E[Y\mid X]=1+\dfrac1{6X+3}

This random variable is undefined only when X=-\frac12 which is outside the support of f_X, so we have

E[Y]=E\left[1+\dfrac1{6X+3}\right]=\displaystyle\int_0^1\left(1+\frac1{6x+3}\right)f_X(x)\,\mathrm dx=\frac87

5 0
3 years ago
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