The tenth place in this number is 4.<u>4</u>32, so that should be the last digit.
Now, we need to know wether to round up or down. That is determined by the digit that comes after it. <em>If that digit, here it is the hundredth, is 0-4, it rounds down, if it is 5-9, it rounds up</em>. Our next digit is <em>3</em>, which goes into the first category, <em>so the number rounds down</em>, so the tenth remains the same. That leaves us with 4.4.
The tenth decimal place is one to the left of the decimal. The hundreth decimal places is two digits to the right and so on an so forth. Knowing this, you apply the basic rules of rouding. If the digit to the left of the digit being rounded is greater than five, the digit is rounded up one and the others are discarded. In this case, the digit to the left of the digit in subject is less than five, 3. Therefore, the tenth decimal stays the same and the others are discarded.
The first method is by plotting points and then dreaming a line through the points. The second is by using the y intercept and slope the third is applying transformation to the identity function. F(x)=x(x)=x
you just need to count the spaced or numbers till you get to 4 then put 10 then to the power of whatever and its -6 because it started from a small number
