How many bags of seeds will she need

Aubrey played on the playground for 2 1/2 hours. How many minutes did she play?

marshall27 [118]

Aubrey plays for 150 minutes on the playground.

5 0

3 years ago

Read 2 more answers

I need help on this question

Flura [38]

Answer:

you are adding a dollar and 50 cents each time

Step-by-step explanation:

then find your y and x and plot it

6 0

3 years ago

kathy plans to bake 2 types of cookies to take to the party. She needs to be sure she has enough ingredients. The chocolate chip

myrzilka [38]

Answer:

4 11/12

I hope I helped! (If I got it wrong, feel free to tell me I got it wrong)

7 0

3 years ago

Convert the following radian angle into degrees.

NeTakaya

The degree of the radian angle 0.11 is $6.3^{\circ}$

Explanation:

It is given that the radian angle is 0.11

We need to determine the degrees of the radian angle.

To convert the radian into degrees, let us multiply the radian with $\left(\frac{180}{\pi}\right)$

Thus, we have,

$0.11\times\left(\frac{180}{\pi}\right)=\frac{19.8}{\pi}$

It is given that $\pi=3.14$

Substituting $\pi=3.14$ in the above expression, we have,

$\frac{19.8}{3.14} =6.303...$

Rounding off to the nearest tenth, we have,

$6.3^{\circ}$

Thus, the degree of the radian angle 0.11 is $6.3^{\circ}$

4 0

3 years ago

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

6 0

3 years ago