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3 years ago

Find the length of the segment. round to the nearest tenth of a unit P(1,2) Q(5,4)

2 answers:

7 0

Hello,

$d= \sqrt{ (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} } \\ \\ d=\sqrt{ (5-1)^{2}+(4-2)^{2} } \\ \\ d=\sqrt{ 4^{2}+2^{2} } \\ \\ d= \sqrt{16+4} \\ \\ d= \sqrt{20} \\ \\d= \sqrt{2^{2}*5 }\\ \\d= 2\sqrt{5 } \\ \\ d=4.5$

Answer: lenght= 4.5

yuradex [85]3 years ago

7 0

$P(1,2)\ \ \ Q(5,4)\\\\
PQ=\sqrt{(x_Q-x_P)^2+(y_Q-y_P)^2}\\\\
PQ=\sqrt{(5-1)^2+(4-2)^2}=\sqrt{16+4}=\sqrt{20}=2\sqrt{5}\approx4,5\\\\
Length\ of\ this\ segment\ is\ equal\ to\ 4,5.$

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which of the following could be side lenths of a right triangle? A.) 0.9cm, 1.2cm, 1.5cm B.) 0.9cm, 1.5 cm, 1.5cm C.) 0.9 cm, 1.

Gwar [14]

Answer:

The answer A

Step-by-step explanation:

B: You need a side that is longer than 2 equal sides. B is incorrect.

A: Try

9^2 + 12^2 = 15^2 if that works, A will work.

81 + 144 = 225

This works. I used these numbers because they were easier to see.

0.9^2 + 1.2^2 = 1.5^2

0.81 + 1.44 = 2.25

2.25 = 2.25

That is the answer A

But we have to check the other two.

0.9^2 = 0.81

1.2^2 = 1.44

1.8^2 = 3.24 This won't work. 3.24 is just too big.

0.9^2 = 0.81

0.6^2 = 0.36

1.5^2 = 2.25 It's too far away.

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3 years ago

A function is shown f(x)=2/3x+3 what is the value of f(12)

exis [7]

Answer:

55/18

Step-by-step explanation:

f(x) = 2/3*12 +3

= 1/18 +3

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3 years ago

Rectangle A measures 10 inches by 8 inches. Rectangle B is an enlarged copy of Rectangle A. Select all of the measurement pairs

Fudgin [204]

Answer:

See Explanation

Step-by-step explanation:

Given

Rectangle A:

$Length: 10\ in$

$Width: 8\ in$

Required

Determine the possible dimensions of Rectangle B

The question has missing options; however, the question can still be solved.

Rectangle B being an enlarged copy of A implies that the dimension of A A is enlarged in equal proportion to form B

Take for instance, the measurements of Rectangle B are

$Length: 15 in$

$Width: 12 in$

Divide the corresponding lengths of B by A to get the enlargement ratio

$Ratio = \frac{B}{A}$

For length:

$Ratio = \frac{15}{10}$

$Ratio = 1.5$

For width

$Ratio = \frac{12}{8}$

$Ratio = 1.5$

Notice that both ratios are the same.

For this measurement of B, we can conclude that B is an enlargement of A

Assume another measurements for B

$Length: 20\ in$

$Width: 10\ in$

Calculate Ratios

$Ratio = \frac{B}{A}$

For length:

$Ratio = \frac{20}{10}$

$Ratio = 2$

For width

$Ratio = \frac{10}{8}$

$Ratio = 1.25$

Notice that, both ratios are not equal.

For this measurement of B, we can conclude that B is not an enlargement of A

Conclusively, all you have to do is: determine the ratios of the dimensions of B to A, if the result are equal then B is an enlarged copy of A; if otherwise, then B is not an enlarged copy

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Answer:

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