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Viktor [21]
3 years ago
5

Find the length of the segment. round to the nearest tenth of a unit P(1,2) Q(5,4)

Mathematics
2 answers:
Alborosie3 years ago
7 0
Hello, 

d= \sqrt{ (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}  }  \\  \\ d=\sqrt{ (5-1)^{2}+(4-2)^{2}  } \\  \\ d=\sqrt{ 4^{2}+2^{2}  }  \\  \\ d= \sqrt{16+4}  \\  \\ d= \sqrt{20}  \\  \\d= \sqrt{2^{2}*5 }\\  \\d= 2\sqrt{5 } \\ \\  d=4.5

Answer: lenght= 4.5
yuradex [85]3 years ago
7 0
P(1,2)\ \ \ Q(5,4)\\\\
PQ=\sqrt{(x_Q-x_P)^2+(y_Q-y_P)^2}\\\\
PQ=\sqrt{(5-1)^2+(4-2)^2}=\sqrt{16+4}=\sqrt{20}=2\sqrt{5}\approx4,5\\\\
Length\ of\ this\ segment\ is\ equal\ to\ 4,5.
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Solve -2/3x > 8 or -2/3x < 4.
vekshin1
<h3>Answer: Choice C</h3>

{x | x < -12 or x > -6}

=========================================================

Explanation:

Let's solve the first inequality for x.

(-2/3)x > 8

-2x > 8*3

-2x > 24

x < 24/(-2)

x < -12

The inequality sign flips when we divide both sides by a negative value.

Let's do the same for the second inequality.

(-2/3)x < 4

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x > 12/(-2)

x > -6

The conclusion of each section is that x < -12 or x > -6 which points us to <u>choice C</u> as the final answer.

Side note: The intervals x < -12 and x > -6 do not overlap in any way. There's a gap between the two pieces. We consider these intervals to be disjoint. The number line graph is below.

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Step-by-step explanation:

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Answer:

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Answer:

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