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3 years ago

Can a quadratic function ever be an odd function? Explain why.

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

8 0

No, odd functions are odd degrees
quadratic functions are to 2nd degree (Even)

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What is the Slope and y intercept

Inessa [10]

Answer:

The slope is .075 and the y intercept is -.125

Step-by-step explanation:

8y = .2(3x -5)

Distribute the .2

8y = .6x - 1

Divide by 8

8y/8 = .6x/8 -1/8

y = .075x -.125

This is in slope intercept form y= mx+b where m is the slope and b is the y intercept.

The slope is .075 and the y intercept is -.125

5 0

3 years ago

Kendra was asked to find the number of students who planned to attend the evening symphony performance. She was told that 40 per

navik [9.2K]

Picture related to the question is attached below

Answer:

Kendra should have divided by 2 instead of multiplying by 2

Step-by-step explanation:

40 percent = percentage who plan to attend

100% = total percentage of student

From the question ;

When reducing percentages, division is employed and this the equation should be :

40/2 ÷ 100/2

40/2 * 2/100

20 * 1/50

20/50

= 0.4

0.4 * 50

= 20 students

6 0

2 years ago

Read 2 more answers

CA and CB name the same ray.<br> True<br> False

Maru [420]

Answer:

I think is true good luck

Step-by-step explanation:

4 0

3 years ago

Help me with this math

stellarik [79]

Answer:

(x+2)(x+5) or if you were looking for the x-intercepts they would be -5, and -2

7 0

3 years ago

Read 2 more answers

Pat needs to determine the height of a tree before cutting it down to be sure that it will not fall on a nearby fence. The angle

dem82 [27]

Answer:

229.23 feet.

Step-by-step explanation:

The pictorial representation of the problem is attached herewith.

Our goal is to determine the height, h of the tree in the right triangle given.

In Triangle BOH

$Tan 60^0=\dfrac{h}{x}\\h=xTan 60^0$

Similarly, In Triangle BOL

$Tan 50^0=\dfrac{h}{x+60}\\h=(x+60)Tan 50^0$

Equating the Value of h

$xTan 60^0=(x+60)Tan 50^0\\xTan 60^0=xTan 50^0+60Tan 50^0\\xTan 60^0-xTan 50^0=60Tan 50^0\\x(Tan 60^0-Tan 50^0)=60Tan 50^0\\x=\dfrac{60Tan 50^0}{Tan 60^0-Tan 50^0} ft$

Since we have found the value of x, we can now determine the height, h of the tree.

$h=\left(\dfrac{60Tan 50^0}{Tan 60^0-Tan 50^0}\right)\cdotTan 60^0\\h=229.23 feet$

The height of the tree is 229.23 feet.

5 0

3 years ago