6x
42/6 = 7 (valid), 18/6 = 3 (valid), 12/6 = 2 (valid)
7, 8, 9, 10, and 11 are all not divisible by 12, and 12 is not divisible by 18, so 6 is the highest number.
Also, each number has at least one x, so you can take one out.
Remaining=
6x (7 + 3x^2 + 2x^3)
Answer:
$21473.33
Step-by-step explanation:
Let the original price be x
76% discount gives $153.60
This means 24/100 * x = $153.60
X= 153.60 * 100 /24 = $21473.33
It would stop at 3y+4>11 because the 3y and 4 are unlike terms and can only be divided or multiplied.
Answer:
Step-by-step explanation:
All marbles here are identical. Also, the question isn't concerned about the order in which the marbles are drawn. Thus, all calculations here shall be combinations rather than permutations.
<h3>A)</h3>
How many ways to choose three out of six identical red marbles without replacement?
.
Note that these three expressions are equivalent. They all represent the number of ways to choose 3 out of 6 identical items without replacement.
How many ways to choose three out of all the 6 + 10 + 6 = 22 marbles?
.
The probability of choosing three red marbles out of these 22 marbles will be:
.
<h3>B)</h3>
How many ways to choose two out of six identical red marbles without replacement?
.
How many ways to choose one out of 10 + 6 = 16 non-red marbles?
.
Choosing two red marbles does not influence the number of ways of choosing a non-red marble. Both event happen and are independent of each other. Apply the product rule to find the number of ways of choosing two red marbles and one non-red marble out of the pile of 22.
.
Probability:
.
Double check that the order doesn't matter here.
<h3>C)</h3>
None of the marbles are red. In other words, all three marbles are chosen out of a pile of 10 + 6 = 16 white and blue marbles. Number of ways to do so:
.
Probability:
.
(1,7), since that's the point where both lines intersect.