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lisov135 [29]
3 years ago
7

Ali's dining room table is round and has a radius of 4.5 ft. What is the tabletop's area? Use 3.14 for pi.

Mathematics
2 answers:
Reika [66]3 years ago
5 0

Answer:

2.3

Step-by-step explanation:

Tanzania [10]3 years ago
3 0

Answer:

63.6 ft2

Step-by-step explanation:

Are is pi*r2

3.14*4.52

63.6

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Find the greatest common factor of these three expressions.
leva [86]
6x

42/6 = 7 (valid), 18/6 = 3 (valid), 12/6 = 2 (valid)

7, 8, 9, 10, and 11 are all not divisible by 12, and 12 is not divisible by 18, so 6 is the highest number.

Also, each number has at least one x, so you can take one out.

Remaining=
6x (7 + 3x^2 + 2x^3)

3 0
3 years ago
At a sale this week, a sofa is being sold for $153.60 .This is a 76% discount from the original price. What is the original pric
ad-work [718]

Answer:

$21473.33

Step-by-step explanation:

Let the original price be x

76% discount gives $153.60

This means 24/100 * x = $153.60

X= 153.60 * 100 /24 = $21473.33

4 0
4 years ago
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Solve each inequality. Justify each step (y-) - 4 + 2y > 11
Anna11 [10]
It would stop at 3y+4>11 because the 3y and 4 are unlike terms and can only be divided or multiplied.
4 0
3 years ago
Plssss help
Andre45 [30]

Answer:

  • A) \displaystyle \frac{1}{77}.
  • B) \displaystyle \frac{12}{77}.
  • C) \displaystyle \frac{4}{11}.

Step-by-step explanation:

All marbles here are identical. Also, the question isn't concerned about the order in which the marbles are drawn. Thus, all calculations here shall be combinations rather than permutations.

<h3>A)</h3>

How many ways to choose three out of six identical red marbles without replacement?

\displaystyle _6C_3 = c(6, 3) = {6\choose 3} = 20.

Note that these three expressions are equivalent. They all represent the number of ways to choose 3 out of 6 identical items without replacement.

How many ways to choose three out of all the 6 + 10 + 6 = 22 marbles?

\displaystyle _{22} C_{3} = 1540.

The probability of choosing three red marbles out of these 22 marbles will be:

\displaystyle \frac{\text{Number of ways for choosing three out of six red marbles}}{\text{Number of ways to choose three out of 22 marbles}} = \frac{20}{1540} = \frac{1}{77}.

<h3>B)</h3>

How many ways to choose two out of six identical red marbles without replacement?

\displaystyle _6 C_2 = 15.

How many ways to choose one out of 10 + 6 = 16 non-red marbles?

_{16} C_1=16.

Choosing two red marbles does not influence the number of ways of choosing a non-red marble. Both event happen and are independent of each other. Apply the product rule to find the number of ways of choosing two red marbles and one non-red marble out of the pile of 22.

_6 C_2 \cdot _{16} C_1= 240.

Probability:

\displaystyle \frac{240}{1540} = \frac{12}{77}.

Double check that the order doesn't matter here.

<h3>C)</h3>

None of the marbles are red. In other words, all three marbles are chosen out of a pile of 10 + 6 = 16 white and blue marbles. Number of ways to do so:

_{16} C_{3} = 560.

Probability:

\displaystyle \frac{560}{1540}= \frac{4}{11}.

5 0
4 years ago
Read 2 more answers
Please help 5 points
zloy xaker [14]
(1,7), since that's the point where both lines intersect.
7 0
3 years ago
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