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saul85 [17]
3 years ago
12

Which of the following is equal to √-12?

Mathematics
2 answers:
iren [92.7K]3 years ago
3 0

Answer:

2i√3

Step-by-step explanation: Simplify the radical by breaking the radicand up into a product of known factors.

Hope this helps! :) ~Zane

yarga [219]3 years ago
3 0

For this case we must find an expression equivalent to:

\sqrt {-12}

Then, rewriting:

\sqrt {-1 (12)} =\\\sqrt {-1} * \sqrt {12} =

We know that:

i = \sqrt {-1}\\12 = 4 * 3 = 2 ^ 2 * 3

Then we have:

i * \sqrt {2 ^ 2 * 3} =\\i * 2 \sqrt {3} =

Finally we have:

2i \sqrt {3}

Answer:2i \sqrt {3}

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What is the solution of the equation (x-5)^2+3(x-5)+9=0 use u substitution and the quadratic formula to solve
Schach [20]

Answer:

fff

Step-by-step explanation:

ff

3 0
3 years ago
I NEED HELP PLEASE WITH PART 2, THANKS!
EleoNora [17]

Steps to solve:

-6w - 8 + 15w = 2w - 8 + 7w

~Combine like terms

9w - 8 = 9w - 8

~Add 8 to both sides

9w = 9w

~Divide 9 to both sides

0 = 0

All real numbers are solutions.

Set builder notation: {x | R}

Best of Luck!

8 0
3 years ago
In an experiment, a fair coin is tossed 13 times and the face that appears (H for head or T for tail) for each toss is recorded.
zalisa [80]

Answer:

1) 1 element

2) 13 elements

3) 22 elements

4) 40 elements

Step-by-step explanation:

1) Only one element will have no tails: the event that all the coins are heads.

2) 13 elements will have exactly one tile. Basically you have one element in each position that you can put a tail in.

3) There are {13 \choose 2} = 78 elements that have exactly 2 tails. From those elements we have to remove the only element that starts and ends with a tail and in the middle it has heads only and the elements that starts and ends with a head and in the 11 remaining coins there are exactly 2 tails. For the last case, there are {11 \choose 2} = 55 possibilities, thus, the total amount of elements with one tile in the border and another one in the middle is 78-55-1 = 22

4) We can have:

  • A pair at the start/end and another tail in the middle (this includes a triple at the start/end)
  • One tail at the start/end and a pair in the middle (with heads next to the tail at the start/end)

For the first possibility there are 2 * 11 = 22 possibilities (first decide if the pair starts or ends and then select the remaining tail)

For the second possibility, we have 2*9 = 18 possibilities (first, select if there is a tail at the end or at the start, then put a head next to it and on the other extreme, for the remaining 10 coins, there are 9 possibilities to select 2 cosecutive ones to be tails).

This gives us a total of 18+22 = 40 possibilities.

5 0
3 years ago
Can someone answer this for me just tell me what to pick
Marizza181 [45]

The inequality you require is

The number of bottles left at the end of each day is  48 - 3x. So it is:-

48 - 3x < 10

Solving the inequality to find the last part of question:-

-3x < 10 - 48

-3x < -38

x >  38/3 = 12 2/3

So answer is  13 days.


3 0
3 years ago
The area of a rectangle is represented by the expression 62 – 3x2 + 12x.
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