Steps to solve:
-6w - 8 + 15w = 2w - 8 + 7w
~Combine like terms
9w - 8 = 9w - 8
~Add 8 to both sides
9w = 9w
~Divide 9 to both sides
0 = 0
All real numbers are solutions.
Set builder notation: {x | R}
Best of Luck!
Answer:
1) 1 element
2) 13 elements
3) 22 elements
4) 40 elements
Step-by-step explanation:
1) Only one element will have no tails: the event that all the coins are heads.
2) 13 elements will have exactly one tile. Basically you have one element in each position that you can put a tail in.
3) There are
elements that have exactly 2 tails. From those elements we have to remove the only element that starts and ends with a tail and in the middle it has heads only and the elements that starts and ends with a head and in the 11 remaining coins there are exactly 2 tails. For the last case, there are
possibilities, thus, the total amount of elements with one tile in the border and another one in the middle is 78-55-1 = 22
4) We can have:
- A pair at the start/end and another tail in the middle (this includes a triple at the start/end)
- One tail at the start/end and a pair in the middle (with heads next to the tail at the start/end)
For the first possibility there are 2 * 11 = 22 possibilities (first decide if the pair starts or ends and then select the remaining tail)
For the second possibility, we have 2*9 = 18 possibilities (first, select if there is a tail at the end or at the start, then put a head next to it and on the other extreme, for the remaining 10 coins, there are 9 possibilities to select 2 cosecutive ones to be tails).
This gives us a total of 18+22 = 40 possibilities.
The inequality you require is
The number of bottles left at the end of each day is 48 - 3x. So it is:-
48 - 3x < 10
Solving the inequality to find the last part of question:-
-3x < 10 - 48
-3x < -38
x > 38/3 = 12 2/3
So answer is 13 days.