): If (6x-3)(6x+3)=ax^2-b, what is the value of a? What is the value of b?
1 answer:
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Answer:
Center: (-3,-2)
Radius: √6
The graph is attached.
Step-by-step explanation:
The equation of the circle has the form:
Where (h,k) is the point of the center of the circle and r is the radius of the circle.
The equation given in the problem is
Therefore:
h=-3
k=-2
The center is at (-3,-2)
And the radius is:
Then, you can graph it has you can see in the image attached.
