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Klio2033 [76]
3 years ago
15

): If (6x-3)(6x+3)=ax^2-b, what is the value of a? What is the value of b?

Mathematics
1 answer:
lesantik [10]3 years ago
7 0
Answer: a = 36 and b = 9

Explanation:

(6x-3)(6x+3)

= 36x² - 18x - 18x - 9

= 36x² - 9



(6x-3)(6x+3) = ax² - b

36x² - 9 = ax² - b

a = 36 and b = 9

Hope it helps!
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