probability of one go on vacation and one does not go on vacation is 0.2356 and probability none of them go on vacation is 0.1444
According to a survey, 62% of americans go on vacation each .
two americans are chosen from a group of 100 americans.
what is the probability that one or both of the people chosen does not go on vacation each ?
62% americans go on vacation t
hen 38% americans does not go on vacation
Total group of americans is 100
out of 100 americans 62 go on vacation and 38 does not go on vacation
probability of one go on vacation and one does not go on vacation
= 0.62*0.38
=0.2356
probability none of them go on vacation
= 0.38*0.38
=0.1444
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The answer is -1 because a coefficient is the number in front of the variable which is -1 because there is an invisible 1 before the x
Answer:
See below
Step-by-step explanation:
The initial ordered-pairs are 
We have a rotation of 90 degrees counterclockwise with respect to origin
Note. Previously the points were
After the rotation, we have
Thus, 
Then shifting horizontally to the right 2 units, we get ΔA'B'C'
Thus,
