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Mnenie [13.5K]
3 years ago
12

Help I need this done fast!

Mathematics
1 answer:
wolverine [178]3 years ago
5 0
B

Sorry if I’m wrong...
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Which triangles are right​ triangles? Select all that apply.
Setler79 [48]

Answer:

triangle 1, triangle 3,

Step-by-step explanation:

Triangle 1= 14^{2} + 24^{2} = 772\\196+ 576 = 772

Triangle 2=  is wrong

Triangle 3= 11^{2} + 22^{2} = 605\\121+ 484= 605

Triangle 4= is wrong.

7 0
2 years ago
What is cotangent of A divided by Tangent of A?
grin007 [14]
tan A =  \frac{1}{cot A} cot A =  \frac{1}{tan A} 

\frac{1}{cot A} / \frac{1}{tanA} =1

4 0
3 years ago
What is the simpler form of (2x-6)^2
KatRina [158]
(2x - 6)^2 = (2x - 6)(2x - 6) = 4x^2 - 12x - 12x + 36 = 4x^2 - 24x + 36
6 0
3 years ago
Read 2 more answers
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
2 years ago
Solve the equation 8y + 4x=5 for y. Oy=32x + 40 0 y = 40 – 32x o y= J +3 5. o y=​
Liono4ka [1.6K]

Answer:

The Last One

Step-by-step explanation:

8y = 5 - 4x

y = 5/8 - (1/2)x

5 0
2 years ago
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