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2 years ago

In the figure below, mZPSQ = 70° and m_SRQ = 27°.

Mathematics

2 answers:

Sveta_85 [38]2 years ago

3 0

Answer:

273984828kdjsssdjdjdjdjddddeejddfj

dybincka [34]2 years ago

3 0

Answer:

Step-by-step explanation:

First, all triangles' angles add up to 180 degrees. We would first have to figure out the measure of <QSR. To do this, add all angles you know. We have to assume <SQR is 90 degrees since it is aligned with the other triangle. So, 90+27=117. Then, we would do 180-117 to find <QSR since all triangles angles 180 degrees. This is 63. Then, because these triangles are along a 180 degree (straight) line, we would do <PSQ, 70, so 70+63 which equal 133, and then 180-133 since all angles equal 180. This is 47.

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A hot air balloon is flying at an altitude of 800 feet. A passenger takes a picture of the top of a tree and estimates that the

nalin [4]

The height of the tree given the depression angle to the top and the base

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Correct response:

The height of the tree is approximately <u>79.58 feet</u>

<h3 /><h3>Methods used for the calculation of the height of the tree</h3>

Given:

Altitude of the hot air balloon = 800 feet

Angle of depression to top of tree = 43°

Angle of depression to base of tree = 46°

Required:

Height of tree

Solution:

The horizontal distance of the balloon from the tree is given as follows;

$\displaystyle tan(46^{\circ}) = \frac{Altitude \ of \ balloon}{Horizontal \ distance \ from \ tree} = \mathbf{\frac{800 \, feet}{Horizontal \ distance \ from \ tree}}$

Therefore;

$\displaystyle Horizontal \ distance \ of \ balloon \ from \ tree = \frac{800 \ feet}{tan(46^{\circ})}$

$\displaystyle tan(43^{\circ}) = \mathbf{\frac{Height \ of \ balloon \ above \ tree}{\dfrac{800 \, feet}{tan(46^{\circ})} }}$

Therefore;

$\displaystyle Height \ of \ balloon \ above \ tree = tan(43^{\circ}) \times \frac{800 \, feet}{tan(46^{\circ})}$

Height of tree = Altitude of balloon - Height of balloon above tree

Therefore;

$\displaystyle Height \ of \ tree = 800 \, feet - tan(43^{\circ}) \times \frac{800 \, feet}{tan(46^{\circ})} \approx \underline{ 79.58 \, feet}$

Learn more about angle of elevation and depression here:

brainly.com/question/1978238

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zalisa [80]

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