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3 years ago

1. Amani is organizing her sticker collection.

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

3 0

39 stickers in each album

trapecia [35]3 years ago

3 0

Answer:

39 stickers

Step-by-step explanation:

83 + 27 + 46 = 156

156/4 = 39

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Please help. Thank you

madam [21]

Answer:

Step-by-step explanation:

Pythagoras theroem

$\sqrt{(( {32}^{2}) + {12}^{2} ) }$

= 4√73

8 0

2 years ago

Your neighbor has a bag with 5 oranges and 7 apples in it. You will be receiving two pieces of fruit from your neighbor. What is

Snezhnost [94]

Answer:

31.82% probability that you will receive 2 apples.

Step-by-step explanation:

The fruits are removed from the bag, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

5 + 7 = 12 total fruits, which means that $N = 12$

7 apples, which means that $k = 7$

You receive 2 fruits, which means that $n = 2$

What is the probability, in percent, that you will receive 2 apples, assuming she removes them from the bag in random order?

This is, as a proportion, P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,12,2,7) = \frac{C_{7,2}*C_{5,0}}{C_{12,2}} = 0.3182$

0.3182*100% = 31.82%

31.82% probability that you will receive 2 apples.

4 0

3 years ago

How many thousands are in 327,412?

Alexxandr [17]

Answer:

327

Step-by-step explanation:

In the thousands cateragory of the number lies the numbers 327 giving you your answer

8 0

3 years ago

50 POINTS !! PLEASE HELP ILL GIVE BRAINLIEST !!

dybincka [34]

Answer:

3.9 miles

Step-by-step explanation:

Use phytagoras theorem

c²=a²+b²

4²=1²+b²

16=1+b²

b²=16-1

b²=15

$\sqrt{15}$

b= 3.872

≈3.9miles

6 0

3 years ago

The weight of National Football League (NFL) players has increased steadily, gaining up to 1.5 lb. per year since 1942. Accordin

GuDViN [60]

Answer:

The probability that the sample mean weight will be more than 262 lb is 0.0047.

Step-by-step explanation:

The random variable X can be defined as the weight of National Football League (NFL) players now.

The mean weight is, μ = 252.8 lb.

The standard deviation of the weights is, σ = 25 lb.

A random sample of n = 50 NFL players are selected.

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The sample of players selected is quite large, i.e. n = 50 > 30, so the central limit theorem can be used to approximate the distribution of sample means.

$\bar X\sim N(\mu_{\bar x}=252.8,\ \sigma_{\bar x}=3.536)$

Compute the probability that the sample mean weight will be more than 262 lb as follows:

$P(\bar X>262)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{262-252.8}{3.536})\\\\=P(Z>2.60)\\\\=1-P(Z$

*Use a z-table for the probability.

Thus, the probability that the sample mean weight will be more than 262 lb is 0.0047.

6 0

3 years ago