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ivann1987 [24]
3 years ago
12

Si tienes 5 manzanas para comer durante la semana y te comes el 20% el primer día cuántas manzanas quedan para el resto de la se

man?
Mathematics
2 answers:
mart [117]3 years ago
7 0

Answer: El o Ella tiene 4 manazanas izquierda comer para el semana

Step-by-step explanation: Si necesitas ayuda con algo más estoy disponible generalmente de 9 a.m. a 3:50 p.m.

Vanyuwa [196]3 years ago
5 0

Answer:

4.8

Step-by-step explanation:

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Solve for x. Round your answer to the nearest tenth.
zlopas [31]

Answer:

By Pythagorean theorem:

c^2=a^2+b^2

x=\sqrt{15^2+33^2}

x=36.25

x=36.3

7 0
2 years ago
What is the answer to (14x-35)/7=7
IceJOKER [234]
Your not being very discriptive... BUT if you are finding 'x'...
(14x-35)/17=7
*17 *17
14x-35=119
+35 +35
14x=154
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x=11
6 0
3 years ago
Suppose that the function f is defined, for all real numbers, as follows.
Veseljchak [2.6K]

The solutions of the function are:

  • When f(x) = -4, the solution is -4
  • When f(x) = -2, the solution is -5/2
  • When f(x) = 0, the solution is -1

<h3>How to solve for the equation </h3>

The equation is given as

\frac{3}{4} x-1\\\\

When x = -4

3/4 * -4 -1

= -12/4 - 1

= -4

When x = -2

3/4*(-4) - 1

= -6/4 - 1/1

Take the lcm

-10/4

= -5/2

When x = 0

3/4(0) - 1

= -1

When f(x) = -4, the solution is -4

When f(x) = -2, the solution is -5/2

When f(x) = 0, the solution is -1

Read more on real numbers here:

brainly.com/question/155227

#SPJ1

6 0
2 years ago
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C

The third can be found by integrating by parts:

u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8

\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C

8 0
3 years ago
So you may see more than one post abt these bc its due at 11:59 lol​
dusya [7]

Answer:

quadrilateral

<3

Step-by-step explanation:

8 0
3 years ago
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