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Anna71 [15]
3 years ago
8

Please answer in complete sentences. Fully answer all questions. A community sponsored a charity square dance where admission wa

s $3 for adults and $1.50 for children. If 168 people attended the dance and the money raised was $432. What are the two systems of equations that you could write to solve this problem? What method would you use to solve the system? Why? How many adults and how many children attended the dance? Explain how you have the correct number of adults and children.
Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

3

Step-by-step explanation:

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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
Help please Im bout to fail.....
max2010maxim [7]

Answer:

it's the second to last one on the right side

3 0
3 years ago
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Consider this figure. Enter the measure of
kotykmax [81]

Step-by-step explanation:

4x + 7x + 2° = 90° { being complementary angles }

11x = 90° - 2°

11x = 88°

x = 88° / 11

x = 8°

<YVZ = <em>7</em><em> </em><em>*</em><em> </em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>2</em><em>°</em><em> </em><em>=</em><em> </em><em>5</em><em>8</em><em>°</em>

<em>Hope </em><em>it </em><em>will </em><em>help </em><em>:</em><em>)</em>

3 0
3 years ago
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the table compares the time at which jayden got on the bus to school (in minutes after 8 am) and the duration of the ride (in mi
seropon [69]

Answer: The answer is no, the duration of the ride can’t be represented as a function of the time Jayden got on the bus.

4 0
3 years ago
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2. Find the value of <img src="https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B1728%7D%20%2B%20100%20%5Csqrt%5B4%5D%7B81%7D%20-%20%286
Taya2010 [7]

Answer:

(b) 0

Step-by-step explanation:

Assuming a typo in the last term:

5 (1728)^(1/3) + 100(81)^(1/4) - ( 6(10)^(1/2) )^2

=5(12) + 100(3) -36(10)

=60+300-360

=0

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3 years ago
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