I don’t know I’m sorry I need points look it up on online
FIRST PARTWe need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative
Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached
Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13
cos α = side adjacent to the angle / hypotenuse
cos α = -5/13
Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

SECOND PARTSolve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β



Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β



Find tan (α - β)


Simplify the denominator


Simplify the numerator


Simplify the fraction

If I'm correct the answer would be C.) hope this help
Answer:
x
Step-by-step explanation:
We are given that measure of an exterior angle which are drawn at vertex M=x
We have to find the value of measurement of angle L+measurement of angle N.
Exterior angle:It is defined as that angle of triangle which is formed by the one side of triangle and the extension of an adjacent side of triangle. The measure of exterior angle is equal to sum of measures of two non-adjacent interior angles of a triangle.
Angle L and angle N are two non-adjacent angles of a given triangle LMN.
By definition of exterior angle
x=Measure of angle L+Measure of angle N
Sorry but where is the picture? I’m confused..