Answer:
0.75 U.S. dollars
Step-by-step explanation:
Answer:
i dont know how to help
Step-by-step explanation:
Answer:
We know that:
There is a total of 81 houses:
51 had a finished basement.
56 had a three-car garage.
37 had a finished basement and a three-car garage.
a) How many had a finished basement but not a three-car garage?
51 had a finished basement, and 37 have a finished basement and the garage, then:
51 - 37 = 14 hoses have only the basement.
b) How many had a three-car garage but not a finished basement?
Same reasoning as above:
56 - 37 = 19 houses only have the garage.
c) How many had either a finished basement or a three-car garage?
Now we only count the ones that have one finished thing, in this case, we already found the number of houses that have only the garage or only the basement, then the number of houses that either had a finished basement or a finished garage is:
19 + 18 = 37 houses.
For this case we have the following function:
y = 9 (3) ^ x
Applying the following transformations we have:
Horizontal translations
Suppose that h> 0
To graph y = f (x-h), move the graph of h units to the right.
y = 9 (3) ^ (x-2)
Vertical translations
Suppose that k> 0
To graph y = f (x) -k, move the graph of k units down.
y = 9 (3) ^ (x-2) - 6
Answer:
2 units to the right
6 units down
Take the radius squared 10*10=100 then times that by pi which equals 314 then by 16 which is 5,024 then multiply that by 75 and get 376,800
