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dybincka [34]
3 years ago
15

Which describes how to find the solution to 5k>22?

Mathematics
1 answer:
neonofarm [45]3 years ago
8 0
Just google it its way easy
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Help me please it’s due today
AnnZ [28]

Answer:RTP,NM, X=7

Step-by-step explanation:

Tinanatamad akong isulat ang step by step sorry

4 0
3 years ago
Need help with question 3. ASAP PLS. Much appreciated :)
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Emma is running faster than Maggie. The point on the graph where the two lines intersect represents the spot on the running track where Maggie and Emma are at the same distance from the starting point.
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4 0
3 years ago
How does the value of the digit 2 in 2000 compare with the value of the digit 2 in 200
iragen [17]

Answer:

The value of 2 in 2000 is 10 times greater than the value of 2 in 200

Step-by-step explanation:

from the value of 2 in 200 to reach 2000, it takes 10 times as much because we're moving only one place (which is the thousand's digit).

6 0
3 years ago
Multiply. Answers should be in simplest form.<br> 3/7 x10
chubhunter [2.5K]

Answer:

4.28

I think this it. I used a calculator online to help solve this problem. I don't know what the answer is but I used an online calculator to solve the problem. I rounded the answer to the nearest hundreth.

5 0
3 years ago
Create three geometric sequences of your own (including one that is decreasing). Extend your sequences to include five terms. Th
Karo-lina-s [1.5K]

Answer:

a)  a_n=5\,\,(2)^{n-1}

b)  b_n=100\,\,(\frac{1}{2} )^{n-1}

c)  c_n=160\,\,(-\frac{1}{2} )^{n-1}

Step-by-step explanation:

a)  Geometric sequence with first term 5 and common ratio 2, where the nth term can be calculated via:

a_n=5\,\,(2)^{n-1}

The first five terms are: a_1=5;\,\,\,a_2=10;\,\,\,a_3=20; \,\,\,a_4=40;\,\,\,a_5=80

b) Geometric sequence with first term 100 and common ratio 1/2, where the nth term can be calculated via:

b_n=100\,\,(\frac{1}{2} )^{n-1}

The first five terms are: a_1=100;\,\,\,a_2=50;\,\,\,a_3=25; \,\,\,a_4=12.5;\,\,\,a_5=6.25

c)  Geometric sequence with first term 160 and common ratio -1/2, where the nth term can be calculated via:

c_n=160\,\,(-\frac{1}{2} )^{n-1}

The first five terms are: a_1=160;\,\,\,a_2=-80;\,\,\,a_3=40; \,\,\,a_4=-20;\,\,\,a_5=10

4 0
3 years ago
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