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SVEN [57.7K]
3 years ago
5

Help me im so sad determine the values of X for which f(x) is defined ​

Mathematics
1 answer:
eimsori [14]3 years ago
4 0

Answer:

f(x) =  \frac{(2x - 1)(3x - 2)}{9x - 4}  \\  open \: brackets \\  =  \frac{(6 {x}^{2} - 4x - 3x + 2) }{9x - 4}  \\  =  \frac{6 {x}^{2} - 7x + 2 }{9x - 4}  \\ let \: x \: be \: 1 \\ f(1) =  \frac{(6 - 7 + 2)}{(9 - 4)}  \\  =  \frac{1}{5}

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oksano4ka [1.4K]
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7 0
3 years ago
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DiKsa [7]

Answer:

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3 years ago
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egoroff_w [7]
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3 0
4 years ago
What is y=2/3x-4 in standard form
makkiz [27]

Answer:

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4 0
3 years ago
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