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zlopas [31]
3 years ago
10

Evaluate. 10squared +6⋅7+8 70 142 150 190

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
7 0

Answer:

the answer is 150. this is thw answer

Viefleur [7K]3 years ago
5 0

666.7

Google helps but if you think through it and read in between the lines it makes since and do it when pencil and paper to think it out.

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What fraction of a circle does an arc measure of 30 degrees encompass?
Naddika [18.5K]

Answer:

\frac{1}{12}

Step-by-step explanation:

A full circle consists of 360°, so we can write the fraction of this arc as \frac{30}{360}, which can be simplified to \frac{1}{12} by dividing the numerator and denominator by 30.

**This content involves simplifying fractions and knowledge on the angle sum of a circle which you may wish to revise. I'm always happy to help!

3 0
3 years ago
Use the distributive property to remove the parentheses.<br> 3 (v - 6)
liq [111]
3v - 18. I hope this helped
6 0
3 years ago
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Openstudt what are the coordinates of the turning point for the function f(x) = (x − 2)3 + 1? (−2, −1) (−2, 1) (2, −1) (2, 1)
Dominik [7]

f(x) = (x - 2)^3 + 1

Find the derivative:-

f'(x) =   3(x -2)^2   This = 0 at the turning points:-

so 3(x - 2)^2 =  

giving x = 2 .  When x = 2     f(x)  =  3(2-2)^3 + 1 = 1

Answer is (2, 1)


3 0
3 years ago
Expand the following:<br> 1/5 (10x-25)
mario62 [17]
<span>This must be your answer:
Expanded: 1/5 x 10x + 1/5 x -25 </span>
3 0
4 years ago
Prove the formula sin 3 A + sin A = 4 sin A cos2A
pantera1 [17]

We proved that formula using the trigonometry relations sin3A + sinA = 4sinAcos^2A.

In the given question,

We have to prove the formula sin 3A+sin A = 4sinAcos^2A

The given expression is sin 3A+sin A = 4sinAcos^2A

To prove the formula we take the left side terms to the right side terms

The left side is sin 3A+sin A.

As we know that sin 3A = 3sinA − 4sin^3A

To solve the left side we put the value of sin 3A in sin 3A+sin A.

=sin 3A+sin A

=3sinA − 4sin^3A+sin A

Simplifying

= (3sinA+sin A) − 4sin^3A

= 4sinA − 4sin^3A

Taking 4sinA common from both terms

= 4sinA(1 − sin^2A)

As we know that cos^2A=1 − sin^2A. So

= 4sinAcos^2A

We proved the right hand side.

To learn more about formula of trigonometry terms link is here

brainly.com/question/15270423

#SPJ1

5 0
2 years ago
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