If y varies directly as the square of x, that means that y=k*x^2. Plugging y=100 and x=5 into it, we get 100=k*5^2=k*25. Dividing by both sides, we get k=100/25=4. Going back to the original equation, we now know that y=4*x^2. Plugging 9=x in, we get 4*9^2=4*81=324=y
Answer: y=(3)/(2)x+5
Step-by-step explanation:
For this case we have the following equation:

If we add 1 to both sides of the equation we have:

Dividing between 2 on both sides of the equation we have:

The graph of the solution is shown in the attached figure.
Answer:
See attached image
Answer:
The length of diagonal BD is 11·(1 + √3)
The length of diagonal AC = 22
Step-by-step explanation:
The given data are;
Quadrilateral ABCD = A kite
The length of segment AD = 22
The measure of ∠DAE = 60°
The measure of ∠BCEE = 45°
Whereby, triangle ΔADE = A right triangle, and DE is the perpendicular bisector of AC, by trigonometric ratio, we have;
AE = EC
DE = 22 × sin(60°) = 11·√3
AE = 22 × cos(60°) = 11
∴ AE = EC = 11
BE = EC × tan(∠BCE) = 11 × tan(45°) = 11
The length of the diagonal BD = BE + DE (By segment addition property)
∴ BD = 11 + 11·√3 = 11·(1 + √3)
The length of diagonal BD = 11·(1 + √3)
The length of diagonal AC = AE + EC
∴ AC + 11 + 11 = 22
The length of diagonal AC = 22.
Answer:
7
Step-by-step explanation:
2x-3=11
14=2x
x=7
the answer is 7.