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kykrilka [37]
2 years ago
11

A copy machine makes 32 copies per minute. how many copies does it make in 4 minutes and 45 seconds?

Mathematics
1 answer:
emmainna [20.7K]2 years ago
7 0

152

Step-by-step explanation:

45 seconds = 45/60 minutes = 3/4 minutes . Number of copies = 4*32 + (3/4)*32 = 128 + 24 = 152

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Can someone pls help me on question 8) plss thank you!! I will give a brainstar Question 8!!
Korolek [52]

Answer:

$226

Step-by-step explanation:

1. define the variable x

x = # of days to rent the carpet cleaner

2. substitute x for 7 days

c(7) = 30(7) + 16

3. solve

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These triangles are not drawn to scale. Use the Pythagorean Theorem to determine which triangle is a right triangle. Question 4
Svetach [21]

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Read 2 more answers
Find the solution of the inequality -3n < 81
posledela

Answer:

n<-27

Step-by-step explanation:

you have to get n by itself, to do this divide -3 from both sides of the equations.

-3n/-3<81/-3

n<-27

the answer is n<-27

8 0
3 years ago
5x – 12y – 17 = 0<br> 1*9(x + 2) - (y + 1) + 3 = 0
valentina_108 [34]

Answer: x=\frac{12y+17}{5}

y=\frac{-5x+17}{-12}

x=\frac{y-20}{9}

y=9x+20

Step-by-step explanation:

5x-12y-17=0 (plus 17 from both sides)

5x-12y=17 (plus 12y from both sides)

5x=12y+17 (divide 5 from everything)

x=\frac{12y+17}{5}

5x-12y-17=0 (plus 17 from both sides)

5x-12y=17 (minus 5x from both sides)

-12y=-5x+17 (divide everything by -12)

y=\frac{-5x+17}{-12}

1*9(x+2)-(y+1)+3=0 (distribute 9 to x and to 2) (distribute -1 to y and to 1)

1*9x+18-y-1+3=0 (times 9x by 1)

9x+18-y-1+3=0 (combine like terms)

9x-y+20=0 (minus 20 from both sides)

9x-y=-20 (plus y to both sides)

9x=y-20 (divide 9 from both sides)

x=\frac{y-20}{9}

1*9(x+2)-(y+1)+3=0 (distribute 9 to x and to 2) (distribute -1 to y and to 1)

1*9x+18-y-1+3=0 (times 9x by 1)

9x+18-y-1+3=0 (combine like terms)

9x-y+20=0 (minus 20 from both sides)

9x-y=-20 (minus 9x from both sides)

-y=-9x-20 (divide -1 from everything)

y=9x+20

3 0
3 years ago
Suppose you are managing 16 employees, and you need to form three teams to work on different projects. Assume that all employees
valentina_108 [34]

Answer:

4380 ways

Step-by-step explanation:

We have to form 3 project of 16 employees, they tell us that the first project must have 5 employees, therefore we must find the number of combinations to choose 5 of 16 (16C5)

We have nCr = n! / (R! * (N-r)!)

replacing we have:

1st project:

16C5 = 16! / (5! * (16-5)!) = 4368 combinations

Now in the second project we must choose 1 employee, but not 16 but 11 available, therefore it would be to find the number of combinations to choose 1 of 11 (11C1)

2nd project:

11C1 = 11! / (1! * (11-1)!) = 11 combinations

For the third project we must choose 10 employees, but since we only have 10 available, we can only do a combination of this, since 10C10 = 1, therefore:

3rd project: 1 combination

The total number of combinations fro selecting 16 employees for each project would be:

4368 + 11 + 1 = 4380 combinations, that is, there are 4380 different ways of forming projects with the given conditions.

3 0
3 years ago
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