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jasenka [17]
3 years ago
11

Using the half angle formula, what is the exact value of Cos11pi/12?

Mathematics
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

- \frac{1}{2}\sqrt{2+\sqrt{3} }

Step-by-step explanation:

Using the half angle formula

• cos(\frac{x}{2}) = \sqrt{\frac{1+cosx}{2} }

here \frac{x}{2} = \frac{11\pi }{12}, hence

x = \frac{11\pi }{6}

and cos (\frac{11\pi }{6}) = cos(\frac{\pi }{6}) = \frac{\sqrt{3} }{2}

cos (\frac{11\pi }{12})

= - \sqrt{\frac{1+\frac{\sqrt{3} }{2} }{2} }

= - \sqrt{\frac{2+\sqrt{3} }{4} } = - \frac{1}{2}\sqrt{2+\sqrt{3} }

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The bridge has been shown in the figure.

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x^2=4ay\;\cdots(i)

where a is an arbitrary constant (distance between focus and vertex of the parabola).

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The point P_1(10,-1.72225) and P_2(-10,-1.72225) represent the point on the bridge at a distance of 10 feet from its center.

The distance of these points from the x-axis is d=1.72225 feet and the distance of the base of the bridge from the x-axis is h=40 feet.

Hence, height from the base of the bridge at 10 feet from its center

= h-d

=40-1.72225=38.27775 feet.

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3 years ago
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