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Answer with explanation</u>
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Let p be the population proportion of parents who had children in grades K-12 were satisfied with the quality of education the students receive.
Set of hypothesis :
Confidence interval for population proportion is given by :-
, where
n= sample size
= sample proportion
and 
is the two-tailed z-value for confidence level (c).
As per given ,
Sample size of parents : n= 1085
Number of parents indicated that they were satisfied= 466
Sample proportion : 
Critical value for 90% confidence interval : 
( by z-value table)
Now, the 90% confidence interval :
Thus , the 90% confidence interval: (0.4043, 0.4537).
Since 0.43 lies in 90% confidence interval , it means we do not have enough evidence to reject the null hypothesis .
i.e. We are have no evidence that parents' attitudes toward the quality of education have changed.
Answer:
She will walk and run 148.2 miles in a year
Step-by-step explanation:
She walks: 0.75+0.5=1.25 miles each week
And: 1.25 *52=65 miles a year
She runs : 1.6 miles a week
And: 1.6*52 =83.2 miles a year
Total miles : 83.2+65=148.2 miles
I believe that the answer is 100,000
Answer:
the point is (3, 3) . . . . . . y = 3
Step-by-step explanation:
Write the point-slope equation of the line through the point you know. Then evaluate that equation for x=3 to see what the value of y is.
Point-slope form:
y = m(x -h) +k . . . . slope m through point (h, k)
y = -1/2(x -9) +0 . . . . line with slope -1/2 through point (9, 0)
For x=3, the value of y is ...
y = -1/2(3 -9) + 0 = -1/2(-6) = 3
The value of y is 3.
Probability of event A ( Tesha will not be picked as a guide ) :
P ( A ) = Number of ways it can happen / Total number of outcomes
P ( A ) = (29 - 2) / 29 = 27 / 29 ≈ 0.93
Answer:
The probability that Tesha will not be picked as a guide is 0.93 or 93 %.
