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densk [106]
3 years ago
6

Help me please and thank you

Mathematics
1 answer:
nikklg [1K]3 years ago
7 0

Step-by-step explanation:

I can't see it make it bigger

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Find an equation in standard form of the parabola passing through the points (1, -2), (2,-2), (3,-4)
Yuliya22 [10]
The standard form of a parabola is y=ax²+bx+c
use the three given points to find the three unknown constants a, b, and c:
-2=a+b+c............1
-2=4a+2b+c......... 2
-4=9a+3b+c...........3
equation 2 minus equation 1: 3a+b=0..........4
equation 3 minus equation 2: 5a+b=-2.........5
equation 5 minus equation 4: 2a=-2, so a=-1
plug a=-1 in equation 4: -3+b=0, so b=3
Plug a=-1, b=3 in equation 1: -2=-1+3+c, so c=-4
the parabola is y=-x²+3x-4

double check: when x=1, y=-1+3-4=-2
when x=2, y=-4+6-4=-2
when x=3, y=-9+9-4=-4
Yes.


8 0
2 years ago
Given: circle k(O), m∠P=95°, m∠J=110°, m∠LK=125°<br> Find: m∠PJ
IRINA_888 [86]

Answer:

The measure of the arc PJ is 75\°

Step-by-step explanation:

step 1

Find the measure of angle L

we know that

In a inscribed quadrilateral opposite angles are supplementary

so

m

we have

m

substitute

m

m

step 2

Find the measure of arc KJ

we know that

The inscribed angle measures half that of the arc comprising

so

m

substitute the values

95\°=\frac{1}{2}(125\°+arc\ KJ)

190\°=(125\°+arc\ KJ)

arc\ KJ=190\°-125\°=65\°

step 3

Find the measure of arc PJ

we know that

The inscribed angle measures half that of the arc comprising

so

m

substitute the values

70\°=\frac{1}{2}(65\°+arc\ PJ)

140\°=(65\°+arc\ PJ)

arc\ PJ=140\°-65\°=75\°

5 0
2 years ago
More on Areas. Farmer Jones, and his wife, Dr. Jones, both mathematicians, decide to build a fence in their field to keep the sh
Olin [163]

Answer:

Area covered by the fences will be 16.1 unit²

Step-by-step explanation:

Let the first parabola is represented by the function f(x) = 6x²

and second parabola by g(x) = x² + 9

point of intersection of the graphs will be determined when f(x) = g(x)

6x² = x² + 9

5x² = 9

x² = 1.8

x = ± 1.34

Now we will find the area between these curves drawn on the graph.

Area = \int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx

= \int_{-1.34}^{1.34}(5x^{2}-9)dx

= [\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}

= [\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]

= [-4.01+12.06-4.01+12.06]

= 16.1 unit²

6 0
3 years ago
What numbers that have the same sign equal -4 3/5
djverab [1.8K]

Answer:

In mathematics, equality is a relationship between two quantities or, more generally two mathematical expressions, asserting that the quantities have the same value, or that the expressions represent the same mathematical object. The equality between A and B is written A = B, and pronounced A equals B.[1][2] The symbol "=" is called an "equals sign". Two objects that are not equal are said to be distinct.

Step-by-step explanation:

For example:

{\displaystyle x=y}x=y means that x and y denote the same object.[3]

The identity {\displaystyle (x+1)^{2}=x^{2}+2x+1}{\displaystyle (x+1)^{2}=x^{2}+2x+1} means that if x is any number, then the two expressions have the same value. This may also be interpreted as saying that the two sides of the equals sign represent the same function.

{\displaystyle \{x\mid P(x)\}=\{x\mid Q(x)\}}{\displaystyle \{x\mid P(x)\}=\{x\mid Q(x)\}} if and only if {\displaystyle P(x)\Leftrightarrow Q(x).}{\displaystyle P(x)\Leftrightarrow Q(x).} This assertion, which uses set-builder notation, means that if the elements satisfying the property {\displaystyle P(x)}P(x) are the same as the elements satisfying {\displaystyle Q(x),}{\displaystyle Q(x),} then the two uses of the set-builder notation define the same set. This property is often expressed as "two sets that have the same elements are equal." It is one of the usual axioms of set theory, called axiom of extensionality.[4]

5 0
2 years ago
Read 2 more answers
A Chinese restaurant offers buffet takeout for $4.99 per pound. How much does your takeout meal cost?
Degger [83]

Answer:

$7.68

Step-by-step explanation:

4.99/0.65 = $7.68

Hope it helps!

4 0
2 years ago
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