Answers:
It costs $15 for one adult
It costs $10 for one child
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Work Shown:
x = cost for one adult ticket (in dollars)
y = cost for one child ticket (in dollars)
"it costs $35 for one adult and two children" so the first equation is x+2y = 35. Solve for x to get x = -2y+35 (subtract 2y from both sides). We'll use this equation later. See the "replacement" step below.
"it costs $60 for two adults and three children" so the other equation to set up is 2x+3y = 60
Use the substitution rule to get rid of the x (replace it with something equivalent in terms of y) then isolate y
2x+3y = 60
2( x )+3y = 60
2( -2y+35 )+3y = 60 ... replace x with -2y+35
2(-2y)+2(35)+3y = 60
-4y+70+3y = 60
-y+70 = 60
-y+70-70 = 60-70
-y = -10
y = 10
Since y = 10, it costs $10 for one kid to get a ticket.
If y = 10, then x must be...
x = -2y+35
x = -2*10+35 ... replace y with 10
x = -20+35
x = 15
Since x = 15, it costs $15 for one adult ticket.
Answer:
Sarah bought 2 coach tickets and 3 first class tickets.
Step-by-step explanation:
Let c and f represent the numbers of coach and first class tickets purchased. Then c + f = 5, so that c = 5 - f.
The pricing equation is therefore
$380c + $1080f = $4000. Subbing 5 - f for c, we get the revised equation
380(5 - f) + 1080f = 4000.
After simplification, this becomes:
-380f + 1080f = 2100, or
700f = 2100.
Then f = 3 and c = 5 - f = 5 - 3 = 2.
Sarah bought 2 coach tickets and 3 first class tickets.
First we have 8x -5=3x+10, so x =3.
Hence AB =CD =19.
So 38+DA +BC =46, but DA =BC,
38+2DA=46, then 2DA =8,
DA =4.
Answer:
<u>11/12</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>fraction</u><u> </u><u>that</u><u> </u><u>is</u><u> </u><u>closer</u><u> </u><u>to</u><u> </u><u>1</u><u>.</u>
Answer:
35% decrease
Step-by-step explanation:
To find the percent decrease, divide the difference in price by the original price:
(1014 - 659.1) / 1014
354.9 / 1014
= 0.35
So, the percent decrease was 35%
