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densk [106]
3 years ago
6

Help me please and thank you

Mathematics
1 answer:
nikklg [1K]3 years ago
7 0

Step-by-step explanation:

I can't see it make it bigger

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Mai cguvbhjggyh<br> Bhubyhbh
Volgvan
Understandable- have a good day
7 0
3 years ago
The polynomial p(x)=x^3-19x-30 has a known factor of (x+2)
riadik2000 [5.3K]

Answer:

(x+2) (x+3) (x-5)

Step-by-step explanation:

x³-19x-30 = (x+2) (x²+ax-15)  ... x³=x*(1*x²)   while -30= (2)*(-15)

x³ +<u> 0</u>*x² - 19x -30 = x³ + (<u>2+a</u>)x² + (2a-15)x -30

2+a = 0

a = -2

x³-19x-30 = (x+2) (x²-2x-15) = (x+2) (x+3) (x-5)

8 0
3 years ago
Read 2 more answers
576 = 96 × 6
aliya0001 [1]

Answer:

D

Step-by-step explanation

A.96=6+576

B.576=96+6

C. 96=6×576

D. 576=96×6

5 0
2 years ago
A used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a l
Daniel [21]

Answer:

C. 1000 loss.

Step-by-step explanation:

Let x represent purchase price of each car.

We have been given that a used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a loss of 20 percent of the dealer's purchase price for that car.

We can represent the car that dealer sold with 25% profit to find purchase price as:

x+0.25x=20,000

1.25x=20,000

\frac{1.25x}{1.25}=\frac{20,000}{1.25}

x=16,000

Therefore, the purchase price of 1st car was $16,000.

We can represent the car that dealer sold with 20% loss to find purchase price as:

x-0.20x=20,000

0.80x=20,000

\frac{0.80x}{0.80}=\frac{20,000}{0.80}

x=25,000

Therefore, the purchase price of 2nd car was $25,000.

The total purchase price of both cars would be 16,000+25,000=41,000

The total sale price of both cars 20,000+20,000=40,000.

We can see that the sale price of both car is less than purchase price by $1000, so the dealer got a loss of $1000.

Therefore, the dealer's total loss, in dollars, for the two transactions combined was 1000 and option C is the correct choice.

4 0
3 years ago
Which statement comparing x² + 10 and x + x + x is true when x=−5 ?
Lina20 [59]
X^2 + 10 = 35 when x = -5
x + x + x = 3x = -15 when x = -5.

The answer is B because part A just restates the first equation, and Part C determines which is greater. If you want to determine the difference between the two when x = -5, part B is the best answer because it subtracts the product of one of them from the other.
3 0
3 years ago
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