Answer:
C. About 22
Step-by-step explanation:
13.3 + 2.8 + 5.6
= 21.7
Since 21.7 is close to about 22, we can conclude that C is the final answer.
Answer:
The answer is below
Step-by-step explanation:
Given that:
The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.
The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
a) For x < 2:
From normal distribution table, P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%
b) For x = 2:
For x = 11:
From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337
c) For x = 11:
From normal distribution table, P(x < 11) = P(z < 1.67) = 0.9525
d) For x = 2:
For x = 5:
From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) = 0.2033- 0.0188 = 0.1845
e) For x = 5:
From normal distribution table, P(x < 5) = P(z < -0.83) = 0.2033
Answer:
Area = 33 inches squared
Step-by-step explanation:
The formula for the area of a kite is:
Area = ½ × (d)1 × (d)2
To find the first diagonal (d1):
d1 = 7 in + 4 in = 11 in
To find the second diagonal (d2):
The triangles on the right of the kite must be 3 4 5 triangle since it is a right triangle with a hypotenuse of 5 and a side of 4, we know half of a diagonal would be 3 inches.
d2 = 3 in + 3 in = 6 in
Now we can plug the diagonals into the area formula.
Area = ½ × 11 × 6 = 33 inches squared
The wire, the pole and the segment joining the leg of the pole to the wire in the ground form a right triangle whose hypotenuse is the wire, and the side opposite to the angle 36° is the pole.
By right triangle trigonometry, sin36°=(opposite side)/(hypotenuse.)
Substituting, we have 0.588=(opposite side)/220, thus the length of the opposite side, which represents the length of the pole, is
0.588*220 ft=129.3 ft
