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nekit [7.7K]
2 years ago
14

The Millivanil Cinema sold 150 tickets to a movie. Some of these were

Mathematics
1 answer:
yuradex [85]2 years ago
8 0

Answer:

<h3>a)a+c=150,10.25a+7.75c=1470</h3>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • system of linear equation
<h3>let's solve:</h3>

according to the first condition

  • a+c=150

according to the second condition

  • 10.25a+7.75c=1470
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How do I find each measure? Please I need answers ASAP it's due at 1:50
Norma-Jean [14]

Answer:

Angle CAD is 44 degrees

Angle ACD is 44 degrees

Angle ACB is 136 degrees

Angle ABC is 22 degrees

Explanation:

29. Triangle ADC is an isosceles triangle because it has two equal sides.

If segments AD and DC are congruent, then segment AC is the base and the base angles of an isosceles triangle are equal.

Let x be angle CAD.

Let's go ahead x;

\begin{gathered} 92+x+x=180\text{ (sum of angles in a triangle)} \\ 92+2x=180 \\ 2x=180-92 \\ 2x=88 \\ x=\frac{88}{2} \\ \therefore x=44^{\circ} \end{gathered}

Therefore, measure of angle CAD is 44 degrees.

30. Measure of angle ACD is 44 degrees (Base angles of an isosceles triangle are equal)

31. Let angle ACB be y,

Let's go ahead and find measure of angle ACB;

\begin{gathered} 44+y=180\text{     (angles on a straight line)} \\ y=180-44 \\ \therefore y=136^{\circ} \end{gathered}

So measure of angle ACB is 136 degrees.

32. Let angle ABC be z.

Triangle ACB is also an isosceles triangle so the base angles are the same.

Let's go ahead and find z;

\begin{gathered} 136+z+z=180_{}\text{    (sum of angles in a triangle)} \\ 138+2z=180 \\ 2z=180-136 \\ 2z=44 \\ z=\frac{44}{2} \\ \therefore z=22^{\circ} \end{gathered}

So measure of angle ABC is 22 degrees.

3 0
1 year ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Mama L [17]

(a-b)^2=a^2-2ab+b^2

x^2-10x+27=0\ \ \ \ |-27\\\\x^2-10x=-27\\\\x^2-2\cdot x\cdot5+27=0\ \ \ |+5^2=25\\\\x^2-10x+25=-27+25

5 0
3 years ago
Read 2 more answers
If x+a is a factor of 2x²+2ax+5x+10,find a.
vazorg [7]

If x+a is a factor of the polynomial, it means that -a is a root of the polynomial.

In fact, if a polynomial p(x) has a root x_0 (i.e. p(x_0)=0), then the polynomial is divisible by (x-x_0)

In your case, you know that the polynomial is divisible by (x+a)=(x-(-a)), so -a is a solution.

Let's evaluate p(-a) and set it to zero:

2(-a)^2+2a(-a)+5(-a)+10 = 0 \iff 2a^2-2a^2-5a+10=0 \iff -5a+10 = 0 \iff a = 2

We can check the answer: if a=2 the polynomial becomes

2x^2+2(2)x+5x+10 = 2x^2+9x+10

And we're claiming that -a=-2 is a root of this polynomial:

2(-2)^2+9(-2)+10 = 2\cdot 4 - 18 + 10 = 0

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3 years ago
Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1?
nata0808 [166]

(A- No solution)

Ignore the folloqing;

(12345678901234567890)

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3 years ago
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Compare the integers -13 and 15
agasfer [191]
-13is negative and is 13 spaces away from 0. 15 is positive and is 15 spaces away from 0.
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