Hello!
I believe the next term in the velocity sequence should be 28 cm.
The first thing we must do for this case is to define variables.
We have then:
x: number of slices
y: total cost
We write the linear function that relates the variables.
We have then:

Then, we evaluate the number of slices to find the total cost.
-two slices cost:
We substitute x = 2 in the given equation:

Answer:
two slices = 2.2 $
-ten slices cost:
We substitute x = 10 in the given equation:

Answer:
ten slices = 11 $
-half a slice cost:
We substitute x = 1/2 in the given equation:

Answer:
half a slice = 0.55 $
Answer:
x > -4
Step-by-step explanation:
I just looked it up
But I know this is it
Answer:

Step-by-step explanation:
The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

The answer is C. Once you add the like terms x^2 and 4x^2 you get your answer.