Solution:
<u>Note that:</u>
- Speed = Distance/Time
- Vaimiti speed = 1.1 m/s
- Jabril speed = 1.3 m/s
<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>
- Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
- => Vaimiti's time to reach school: 1500 seconds
<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>
- Jabril's time to reach school: 30 minutes = 30 x 60 seconds
- => Jabril's time to reach school: 1800 seconds
<u>Finding the distance of Vaimiti:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- => 1.1 meters/second = Distance/1500
- => 1.1 x 1500 = Distance
- => 1650 meters = Distance (In meters)
<u>Finding the distance of Jabril:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- 1.3 meters/second = Distance (In meters)/1800 seconds
- => 1.3 x 1800 = Distance (In meters)
- => 2340 meters = Distance (In meters)
This can lead to two possible solutions:
Possible solution #1:
<u>Finding the difference between the two distances:</u>
- 2340 meters - 1650 meters = Difference (In meters)
- => 690 meters
Possible solution #2:
The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.
Hoped this helped!
I think that the answer is a because you only have to terms after you distribute hope this helps you
Answer:17,544,511
Step-by-step explanation: 5929 x 2959= 17,543,911
17,543,911-300= 17,543,611
17,543,611 + 900 = 17,544,511
Answer:
(-19 , -7)
Step-by-step explanation:
y - x = 12
y + x = -25 we sum them to get
2y = -14 , y = -7
then we put -7 instead of y in any of the equations:
-7 - x = 12
-x = 19
x = -19,
finally (x , y) is (-19 , -7)
Answer: negative
Step-by-step explanation:
With yx = zx, then by the Multiplicative Property of Equality, y = z. Since z is a negative integer, then y is also a negative integer. Since yx is positive, with y equal to a negative integer, then x is negative.
