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Svetllana [295]
3 years ago
8

Your pump empties the water from a swimming pool in 8 hours. When your friend's pump is used together with your pump, the pool i

s emptied in 2
hours and 40 minutes. How long (in hours) does it take your friend's pump to empty the pool when working alone?
Mathematics
1 answer:
Lelu [443]3 years ago
4 0

Answer:

4 Hr.

Step-by-step explanation:

Given,

Your pump alone can empties the water in = 8 hrs

With the help of friend pump it take = 2.67 hr

time taken by friends to empty the whole tank = t = ?

We have,

\dfrac{1}{8}+\dfrac{1}{t}= \dfrac{1}{2.67}

\dfrac{1}{t}= \dfrac{1}{2.67}-\dfrac{1}{8}

\dfrac{1}{t}=0.2499

t = \dfrac{1}{0.2499}

t = 4\ hrs

Time taken to empty the tank by the friends pump alone is equal to 4 Hr.

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Need to find P(P|~T)
First step: make a contingency diagram of probabilities (intersection, n)
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therefore
P(P|~T)=P(P n ~T)/P(~T)=0.03/0.31   [ both read off the contingency table ]
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<u>Given</u><u> </u><u>:</u><u>-</u>

  • To graph the line with slope 7 and y intercept -7.

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The graph of the line .

<u>Solution</u><u> </u><u>:</u><u>-</u>

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<u>For</u><u> </u><u>the</u><u> </u><u>graph</u><u> </u><u>see </u><u>attachment</u><u> </u><u>.</u>

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