I need help with this problem too
The limit does not exist. Why? Because the left hand limit DOES NOT equal the right hand limit. Let’s double check:
We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8
5(-0.000001) - 8
-0.000005 - 8
-8.000005
If we would continue the limit (extend the zeros to infinity), we would get exactly
-8
That is our left hand limit.
Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)
abs(-4 - (0.000001))
abs(-4.000001)
4.000001
If we would continue the limit (extend the zeros to infinity), we would get exactly
4
4 does not equal -8, therefore
The limit does not exist
Answer:
03%
Step-by-step explanation:
In this situation Mickey should have drew first 7 cards that are not diamond and then on the 8th attempt she should draw an ace.
Let A be the event of drawing 7 cards which are not diamond and B the event of drawing an ace card. therefore required probability is P(A∩B)=P(A)*P(B)
Now, there are 13 diamonds and 39 other cards. Hence,
P(A)=(
)⁷=0.1335
After drawing 7 non-diamond cards, the 8th card must be a diamond.Hence,
P(B)=
=0.25
Hence, P(A∩B)=P(A)*P(B)=0.1335*0.25=0.033(approximately 0.03,i.e. 3%)
Therefore probability that Mickey will draw her first diamond on the 8th
attempt is 3%
Answer:
-10.25,-3.75 then the next one is -5.75,-10.75
Step-by-step explanation: