Answer:
7
Step-by-step explanation:
Answer:
I need help with this too
Step-by-step explanation:
<u>Solution:</u> 48cm/s^2
<u>Working:</u>
A = s^2
Derivate s^2 (as it is area formula) which gives
dA/dt = 2s dL/dt
dL/dt = 6cm/s
Hence,
2(6) = 12
Side: 4cm
Hence,
dA/dt = (4)(12) = 48cm/s^2
<em>Feel free to mark this as brainliest :D</em>
Answer:
d. 24
Step-by-step explanation:
Answer:
Step-by-step explanation:
The question says that the fish population of an area is being tracked and a certain of 35 were collected,tagged and released.
Later another sample was collected and it revealed that 13% of those fishes caught were the ones tagged previously.
The estimated number of fishes in that area will be:
Let X= number of fishes available in that area
13 percent of fishes caught at the second sample collection were tagged
Number of fishes collected are 35
13/100×X= 35
X= 3500/13
X= 269
The number of fishes in the pond is around 269