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Genrish500 [490]
3 years ago
10

Help I need done ASAP

Mathematics
1 answer:
lora16 [44]3 years ago
3 0

Answer:

3/15 5/25 9/45

Step-by-step explanation:

If you look at 12/60 and simplify it you will get 1/5. Now you just have to apply this to the rest.

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David gained 16 pounds over the winter. he went on a diet and lost 25 pounds. then he regained 4 pounds and weighed 177 pounds.
Alex787 [66]
Let x be the weight of David so 

x+16-25+4 = 177

x-5=177

x= 177+5= 182 pound
8 0
3 years ago
a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s
Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

                         P.Q. = \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s^{2}  = sample variance = 97^{2} = 9409

              n = sample of boxes = 15

           \sigma^{2}  = population variance

<em>Here for constructing 95% confidence interval we have used chi-square test statistics.</em>

So, 95% confidence interval for the population variance, \sigma^{2} is ;

P(5.629 < \chi^{2}__1_4 < 26.12) = 0.95  {As the critical value of chi-square at 14

                                         degree of freedom are 5.629 & 26.12}  

P(5.629 < \frac{(n-1)s^{2} }{\sigma^{2} } < 26.12) = 0.95

P( \frac{5.629 }{(n-1)s^{2} } < \frac{1}{\sigma^{2} } < \frac{26.12 }{(n-1)s^{2} } ) = 0.95

P( \frac{(n-1)s^{2} }{26.12 } < \sigma^{2} < \frac{(n-1)s^{2} }{5.629 } ) = 0.95

<u><em>95% confidence interval for</em></u> \sigma^{2} = [ \frac{(n-1)s^{2} }{26.12 } , \frac{(n-1)s^{2} }{5.629 } ]

                                                  = [ \frac{14 \times 9409 }{26.12 } , \frac{14 \times 9409 }{5.629 } ]

                                                  = [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

6 0
3 years ago
The tax rate is 8.5%<br> What is the tax on 95$?<br><br> Round to the nearest hundredth
Natali [406]
Tax = 8.5% x $95 = $8.08 (nearest hundredth)


Answer: $8.08
5 0
4 years ago
A cardboard box of 32 in^3 volume with a square base and open top is to be constructed. What is the length of base that will min
stiv31 [10]
Volume = are base*height
32 = x^2*h --> h = 32/x^2

surface area =  4x(32/x^2) + x^2 
SA = 128/x + x^2

SA' = -128/x^2 + 2x = 0
2x = 128/x^2
2x^3 = 128
x^3 = 64
x = 4

surface area minimized when length of base is 4 in.

hope this help
6 0
3 years ago
Read 2 more answers
What is 4/7 ÷ 6/9 showing the work
RSB [31]
First flip the second fraction

4/7 divided by 9/6

Next multiply 4 x 9 which is 36

Then multiply 7 x 6 which is 42

Then divide the fraction 36/42

Which since it's not even it would be in decimal form it would be 0.9
5 0
3 years ago
Read 2 more answers
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