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LekaFEV [45]
3 years ago
13

Can you please solve it

Mathematics
1 answer:
mel-nik [20]3 years ago
3 0

Answer:

(9/2)÷(⅗)

(9/2)×(5/3)

9/2 × 5/3=15/2

I would appreciate if my answer is chosen as a brainliest answer

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Look at this triangle.<br> B<br> 8 cm<br> A<br> 22 cm<br> Work out length AB.
brilliants [131]

Answer:

23.41cm

Step-by-step explanation:

Using Pythagoras theorem

a²+b² = c²

Where a and b are sides of the triangle and c is the Hypotenuse.

If we substitute the values

B= 8 cm

A= 22 cm

22²+8² = c²

484 + 64= c²

√548 = c

C= 23.41

Hence, length AB is 23.41cm

CHECK THE ATTACHMENT

7 0
3 years ago
What are the coordinates of the point 1/4 of the way from A to B?
lisov135 [29]

Answer:

7 units

Step-by-step explanation:

8 0
3 years ago
Value of x in 2x-7=35 is​
Reika [66]

Answer:

x=21

Step-by-step explanation:

2x - 7 = 35

    +7    +7

-----------------

2x = 42

-----   -----

 2      2

  x = 21

The answer is 21, hope this helps.

4 0
3 years ago
Read 2 more answers
There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student
Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0
3 years ago
What is that product of 2x + y and 5x -y + 3
poizon [28]

Answer:

10x² + 6x + 3xy + 3y - y²

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, as shown

(2x + y)(5x - y + 3)

= 2x(5x - y + 3) + y(5x - y + 3) ← distributing

= 10x² - 2xy + 6x + 5xy - y² + 3y ( collect like terms )

= 10x² + 6x + 3xy + 3y - y²


7 0
3 years ago
Read 2 more answers
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